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Oksi-84 [34.3K]
3 years ago
12

Ca(OH) =CaO + H2O

Chemistry
1 answer:
DENIUS [597]3 years ago
8 0

Answer:

2 combustion

3 combustion

4 decomposition

5 replacement

6 Decomposition

Note:

Im not really sure if those r right.

It may be right actually.

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Which scientist performed the cathode ray experiment leading to the discovery of electrons
SVETLANKA909090 [29]

The scientist that performed the cathode ray experiment leading to the discovery of electrons is J.J. Thomson.

<h3>What is a cathode ray?</h3>

A cathode ray is a tube that contains negatively charged electrode( that is the cathode) which emits electrons when heated at a low pressure.

The cathode ray was used by the scientist, J.J. Thomson to find the ratio of charge to mass (e/m) of the electrons.

Therefore, the scientist that performed the cathode ray experiment leading to the discovery of electrons is J.J. Thomson.

Learn more about electrons here:

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6 0
2 years ago
How do you find the amount of moles is .032 grams of water and whats the answer
masha68 [24]

Answer:

\boxed {\boxed {\sf 0.0018 \ mol \ H_2 O }}

Explanation:

First, we need to find the molecular mass of water (H₂O).

H₂O has:

  • 2 Hydrogen atoms (subscript of 2)
  • 1 Oxygen atom (implied subscript of 1)

Use the Periodic Table to find the mass of hydrogen and oxygen. Then, multiply by the number of atoms of the element.

  • Hydrogen: 1.0079 g/mol
  • Oxygen: 15.9994 g/mol

There are 2 hydrogen atoms, so multiply the mass by 2.

  • 2 Hydrogen: (1.0079 g/mol)(2)= 2.0158 g/mol

Now, find the mass of H₂O. Add the mass of 2 hydrogen atoms and 1 oxygen atom.

  • 2.0158 g/mol + 15.9994 g/mol = 18.0152 g/mol

Next, find the amount of moles using the molecular mass we just calculated. Set up a ratio.

0.032 \ g  \ H_2 O* \frac{ 1 \ mol \ H_2 O}{18.0152 \ g \ H_2 O}

Multiply. The grams of H₂O will cancel out.

0.032 * \frac{1 \ mol \ H_2 O}{18.0152 }

\frac{0.032 *1 \ mol \ H_2 O}{18.0152 }

0.00177627781 \ mol \ H_2 O

The original measurement given had two significant figures (3,2). We must round to have 2 significant figures. All the zeroes before the 1 are not significant. So, round to the ten thousandth.

The 7 in the hundred thousandth place tells us to round up.

0.0018 \ mol \ H_2 O

There are about <u>0.0018 moles in 0.032 grams.</u>

6 0
3 years ago
ΔH for the formation of CuCl2 from its elements is -220.1 kJ/mol. How many kJ are associated with the formation of 0.30 mole of
otez555 [7]
0.3 * - 220.1 = - 66.03kJ
3 0
3 years ago
Read 2 more answers
Why are physical properties such as hardness or cleavage useful to geologists when identify minerals?
nevsk [136]

Answer:

Physical properties are controlled by the mineral's chemical composition and atomic structure, this combination is distinct in each mineral.

Explanation:

Hello,

Since the physical properties depend on the mineral's chemical composition and the atomic structure (molecular arrangement), we can distinguish different minerals by measuring out hardness, cleavage and other properties in order to analyze their behavior under several conditions and subsequently  use them in a particular application.

Best regards.

5 0
3 years ago
Explain how the Law of Conservation of Mass is demonstrated In photosynthesis and cellular Respiration chemical equations. (Less
Oksi-84 [34.3K]

Explanation:

  • According to the law of conservation of mass, In a chemical reaction, mass is neither created nor destroyed. In other words, the total mass for the reactants needs to equal the total mass of the products.
  • <u><em>In photosynthesis the reactants are 6 carbon dioxide, 6 water and sunlight. The mass of these reactants adds to equal the mass of the products, which are 1 glucose and 6 oxygen. </em></u>
  • <u><em>Cellular respiration on the other hand uses glucose and oxygen gas to produce water, carbon dioxide, and a usable form of energy known as ATP.</em></u>
  • Cellular respiration is the opposite of photosynthesis, such that the products of photosynthesis are the reactants of cellular respiration. Cellular respiration also obeys the law of conservation of mass.
6 0
3 years ago
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