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Oksi-84 [34.3K]
2 years ago
12

Ca(OH) =CaO + H2O

Chemistry
1 answer:
DENIUS [597]2 years ago
8 0

Answer:

2 combustion

3 combustion

4 decomposition

5 replacement

6 Decomposition

Note:

Im not really sure if those r right.

It may be right actually.

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6. For each of the following sets of atoms, rank the atoms from smallest to largest atomic radius.
Alex787 [66]

Answer:

a (F < C < Li)

b (Li < Na < K)

c (Ge < P < O)

d (C < N < Al)

e (Ga < Cl < Al)

4 0
2 years ago
What’s the difference between attractive forces and covalent bonds
Scrat [10]

Answer:

<em>An intramolecular force is between that atoms makeup a molecule. An intermolecular force is between entire molecules. A non-polar covalent bond occurs when the electrons are equally shared between atoms.</em>

3 0
2 years ago
Read 2 more answers
Strontium sulfate becomes less soluble in an aqueous solution when sodium sulfator is added because
horsena [70]

Answer:

The addition of sulfate ions shifts equilibrium to the left.

Explanation:

Hello!

In this case, according to the following ionization of strontium sulfate:

SrSO_3(s)\rightleftharpoons Sr^{2+}+SO_4^{2-}

It is evidenced that when sodium sulfate is added, sulfate, SO_4^{2+} is actually added in to the solution, which causes the equilibrium to shift leftwards according to the Le Ch athelier's principle. Thus, the answer in this case would be:

The addition of sulfate ions shifts equilibrium to the left.

Best regards!

7 0
2 years ago
Read 2 more answers
Uranium-238 decays to lead-206 with a half-life of 4.5 x 109 yr. Determine how much uranium-238 decays in milligrams (to three s
Mamont248 [21]

Answer:

2.15 mg of uranium-238 decays

Explanation:

For decay of radioactive nuclide-

                        N=N_{0}.(\frac{1}{2})^{\frac{t}{t_{\frac{1}{2}}}}

where N is amount of radioactive nuclide after t time, N_{0} is initial amount of radioactive nuclide and t_{\frac{1}{2}} is half life of radioactive nuclide

Here N_{0}=4.60 mg, t=4.1\times 10^{9}yr and t_{\frac{1}{2}}=4.5\times 10^{9}yr

So,N=(4.60mg)\times (\frac{1}{2})^{\frac{4.1\times 10^{9}}{4.5\times 10^{9}}}

so, N = 2.446 mg

mass of uranium-238 decays = (4.60-2.446) mg = 2.15 mg

3 0
3 years ago
Write the chemical formula for the anion present in the aqueous solution of cuso4.
ki77a [65]
SO4 -2, or Sulfate

Hope this helps! :)
6 0
3 years ago
Read 2 more answers
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