Answer:
C. The half-life of C-14 is about 40,000 years.
Explanation:
The only false statement from the options is that the half-life of C-14 is 40,000yrs.
The half-life of an isotope is the time it takes for half of a radioactive material to decay to half of its original amount. C-14 has an half-life of 5730yrs. This implies that during every 5730yrs, C-14 will reduce to half of its initial amount.
- All living organisms contain both stable C-12 and the unstable isotope of C-14
- The lower the C-14 compared to the C-12 ratio in an organism, the older it is.
38.46g
Explanation:
Given parameters:
Mass of CaF₂ = 75.0g
Unknown:
Mass of calcium that can be recovered = ?
Solution:
This is a mass percentage problem and we need to solve it accordingly.
To solve this problem;
Find the molar mass of CaF₂
Find the ratio between the molar mass of Ca and that of CaF₂
Multiply by the given mass
Molar mass of CaF₂ = 40 + (2 x 19) = 78g/mol
Mass of calcium =
x 75 = 38.46g
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Answer:
126.4 g of
are required
Explanation:
Balanced reaction: 
According to balanced reaction-
8 moles of
are produced from 2 moles of 
So, 8.70 moles of
are produced from
moles of
or 2.175 moles of 
Molar mass of
= 58.12 g/mol
So, mass of
required =
= 126.4 g
Hence 126.4 g of
are required
Answer:
240g
Explanation:
Using the equation m=pV, where m=mass, p=density, and V=Volume
m=(6)(40)=240
m=240