<span>(2p + q) ( –3q – 6p + 1)
= -6pq - 12p^2 + 2p - 3q^2 - 6pq + q
= -12p^2 -12pq +2p -3q^2 + q
so answer is b. </span> -12p^2 -12pq +2p -3q^2 + q
Answer:
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Subtract the following:
A) 18 rupees 9 paise from 75 rupees 80 paise.
B) 49 rupees 79 paise from 123 rupees 68 paise.
Answer
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Hint: Use decimal concept.
We know that, 1 rupee = 100 paise. We can reframe these questions as follows:
18 rupees 9 paise from 75 rupees 80 paise
18 rupees 9 paise can be represented as 18.09 rupees and 75 rupees 80 paise can be represented as 75.80 rupees. Now, on subtracting we’ll get,
75.80−18.09−−−−−− 57.71
Which means 57 rupees 71 paise
49 rupees 79 paise from 123 rupees 68 paise
49 rupees 79 paise can be represented as 49.79 rupees and 123 rupees 68 paise can be represented as 123.68 rupees. Now, on subtracting we’ll get,
123.68 −49.79−−−−−− 73.89
Which means 73 rupees 89 paise.
Note: We can also perform the subtraction by making all units the same that are paise and then subtract.
Answer:
a. 1 b. 3/5 or 60%
Step-by-step explanation:
number of favourable events/number of total events
3x/5x = 3/5
Answer:
- g(20) > f(20)
- g(x) exceeds f(x) for any x > 4
Step-by-step explanation:
As with most graphing problems not involving straight lines, it works well to start with a table of values. Pick a few values of x and compute f(x) and g(x) for those values. Plot the points and draw a smooth curve through them.
As in the attached, your table will show that there are two points of intersection between f(x) and g(x), and that for values of x more than 4, g(x) becomes much greater very quickly. Both curves rapidly reach the top of your graph space.
To find whether f(20) or g(20) is greater, you can evaluate the functions for that value of x.
f(20) = 20² = 400
g(20) = 2²⁰ = 1,048,576
Clearly, g(20) has a greater value.
Answer:
See the attachment please.
Step-by-step explanation:
Statistics!! All work is on the picture, plus the boxed answers.