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Stella [2.4K]
3 years ago
14

Describe the extraction of sodium using down cell

Chemistry
2 answers:
mel-nik [20]3 years ago
6 0

Explanation:

thx for the points :))))

Vilka [71]3 years ago
4 0

Explanation:

<em>aBov</em><em>E</em><em> aNs</em><em> iS</em><em> coRRecT</em><em> maRk</em><em> iT</em><em> aS</em><em> bRaInlIEsT</em>!!!!! hummm

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Identify the element below
marysya [2.9K]

Answer:

Beryllium

Explanation:

4 0
3 years ago
How many neutrons are present in an atom with atomic number 9 and mass number 19?​
Kaylis [27]

Answer:

10 neutrons

Explanation:

N=Z-A ie. number of neutrons=mass number-atomic number

N=19-9=10

5 0
3 years ago
Read 2 more answers
Using the Arrhenius concept of acids and bases, identify the Arrhenius acid and base in each of the following reactions: KOH(aq)
Mandarinka [93]

Answer:

Acids:  HNO₃ and HI

Base: KOH

Explanation:

For the Arrhenius concept, acid is a substance that, in water, produces the hydrogen ion (H⁺), and base in the substance that, in water, produces the hydroxyl ion (OH⁻).

For the first reaction then KOH must produce OH⁻ so its a base, and HNO₃ must produce H⁺ so it's an acid.

For the second one, HI must produce H⁺ so it's an acid. For the concept of Arrhenius, (CH₃)₃N can't be classified as a base or as an acid.

7 0
4 years ago
Read 2 more answers
How many atoms are in 0.075 mol of Carbon (C)?
lidiya [134]
The amount of atoms in 1 mole of carbon is 6.022 X 10^3 so with it being 0.075 mole it will be option A 4.5 X 10^22 atoms
5 0
4 years ago
If you have a 1.0 L buffer containing 0.208 M NaHSO3 and 0.134 M Na2SO3, what is the pH of the solution after addition of 50.0 m
Vlada [557]

Answer:

pH = 7.233

Explanation:

Initially, the buffer contains 0.208 moles of NaHSO₃ and 0.134 moles of Na₂SO₃.

NaHSO₃ reacts with NaOH thus:

NaHSO₃ + NaOH → Na₂SO₃ + H₂O

50.0 mL of 1.00 M NaOH are:

0.0500L × (1mol / 1L) = 0.0500moles of NaOH added. That means after the addition are produced  0.0500moles of Na₂SO₃ and consumed 0.0500moles of NaHSO₃. That means final moles of the buffer are:

NaHSO₃: 0.208 mol - 0.050 mol = <em>0.158 mol</em>

Na₂SO₃: 0.134 mol + 0.050 mol = <em>0.184 mol</em>

<em> </em>

As pKa of this buffer is 7.167, it is possible to use H-H equation to find pH, thus:

pH = pKa + log₁₀ [Na₂SO₃] / [NaHSO₃]

pH = 7.167 + log₁₀ [0.184] / [0.158]

<em>pH = 7.233</em>

6 0
3 years ago
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