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mestny [16]
3 years ago
10

Using the Arrhenius concept of acids and bases, identify the Arrhenius acid and base in each of the following reactions: KOH(aq)

HNO3(aq)→KNO3(aq) H2O(l) (CH3)3N(g) HI(g)→(CH3)3NHI(s) Drag the appropriate items to their respective bins.
Chemistry
2 answers:
Mandarinka [93]3 years ago
7 0

Answer:

Acids:  HNO₃ and HI

Base: KOH

Explanation:

For the Arrhenius concept, acid is a substance that, in water, produces the hydrogen ion (H⁺), and base in the substance that, in water, produces the hydroxyl ion (OH⁻).

For the first reaction then KOH must produce OH⁻ so its a base, and HNO₃ must produce H⁺ so it's an acid.

For the second one, HI must produce H⁺ so it's an acid. For the concept of Arrhenius, (CH₃)₃N can't be classified as a base or as an acid.

Mandarinka [93]3 years ago
3 0

Answer: HNO3 , KOH

Explanation:

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1. What kinds of metals are REALLY reactive? why?
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1. Alkali metals (group 1)

2. halogens (Group 17)

3. noble gasses (group 18)

Explanation:

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2. halogens have 7 valence electrons meaning that they just need to gain 1 to get a full octet.

3. Nobel gasses already have a full octet meaning that they don't want to react. (atoms only react to get a full octet)

I hope this helps.  Let me know if anything is unclear.

8 0
3 years ago
a student determined that 8.2 milligrams of oxygen is dissolved in a 1000 gram sample of water at 15 degrees Celsius and 1 atm w
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3 years ago
How many grams of agcl would be needed to make a 4. 0 m solution with a volume of 0. 75 l?
devlian [24]

430 g of AgCl would be needed to make a 4.0m solution with a volume of 0.75 L.

<h3>What is Molarity?</h3>
  • The amount of a substance in a specific volume of solution is known as its molarity (M).
  • The number of moles of a solute per liter of a solution is known as molarity.
<h3>Calculation of Required amount of AgCl</h3>

Remember that mol/L is the unit of molarity (M).

We can compute the necessary number of moles of solute by multiplying the concentration by the liters of solution, according to dimensional analysis.

0.75L×4.0M=3.0mol

Then, using the periodic table's molar mass for AgCl, convert from moles to grams:

3.0mol×143.321gmol=429.963g

The final step is to round to the correct significant figure, which in this case is two: 430g.

Hence, 430 g of AgCl would be needed to make a 4.0m solution with a volume of 0.75 L.

Learn more about Molarity here:
brainly.com/question/8732513

#SPJ4

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