Answer:
What datatable? Picture please!
Explanation:
Answer:
mass = 1.8x10⁻³ kg; number of moles = 4.1x10⁻⁵ kmol; specific volume = 0.55 m³/kg; molar specific volume = 24.4 m³/kmol
Explanation:
By the Avogadro's number, 1 mol of the matter has 6.02x10²³ molecules, thus, the number of moles (n) is the number of molecules presented divided by Avogadro's number:
n = 2.5x10²²/6.02x10²³
n = 0.041 mol
n = 4.1x10⁻⁵ kmol
The molar mass of CO₂ is 44 g/mol (12 g/mol of C + 2*16g/mol of O), and the mass is the number of moles multiplied by the molar mass:
m = 0.041 mol * 44 g/mol
m = 1.804 g
m = 1.8x10⁻³ kg
The specific volume (v) is the volume (1L = 0.001 m³) divided by the mass, and it represents how much volume is presented in each part of the mass:
v = 0.001/1.8x10⁻³
v = 0.55 m³/kg
The molar specific volume (nv) is the volume divided by the number of moles, and it represents how much volume is presented in each part of the mol:
nv = 0.001/4.1x10⁻⁵
nv = 24.4 m³/kmol
Answer:
3)alpha decay because alpha particles have two protons and two neutrons
Explanation:
When a radioactive isotope undergoes a decay, a daughter nucleus or nuclei is/are formed. The mass number and atomic number of the daughter nucleus gives us an idea of the nature of radioactive decay that the parent nucleus underwent.
If the daughter mass number of the daughter nucleus is four units less than that of the parent nucleus and the atomic number of the daughter nucleus is two units less than that of the parent, then such a decay is an alpha decay.
An alpha particle has two protons and two neutrons thus it has a mass number of 4 and an atomic number of two.
Answer:
K= 25.16%
Mn= 34.59%
O= 40.25%
Explanation:
Find the total mass of the compound. You can do this by multiplying by the molar mass.
add them:
40+55+64=159g
Now convert each element individually to grams using molar mass
Divide by the mass of the compound and multiply by 100
Answer:
58.61mL
Explanation:
V1 (initial volume) =?
T1 (initial temperature) = 320 K
V2 (final volume) = 50mL
T2 (final temperature) = 273 K
Using the Charles' law equation V1/T1 = V2/T2
The initial volume of the gas can obtained as follow:
V1/320 = 50/273
Cross multiply to express in linear form
V1 x 273 = 320 x 50
Divide both side by 273
V1 = (320 x 50)/273
V1 = 58.61mL
Therefore, the initial volume of the gas is 58.61mL
