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irina [24]
3 years ago
7

When the switch in the drawing is closed, the current in the coil increases to its equilibrium value. While the current is incre

asing there is an induced current in the metal ring. The ring is free to move. What happens to the ring? a. It does not move b. It jumps upward c. It jumps downward
Physics
1 answer:
Crazy boy [7]3 years ago
3 0

Answer:

the previous correct answer is b

Explanation:

When the circuit is closed in the system, a current is induced that follows the lenz law, which opposes the change that is occurring and therefore the coil increases and the idicidal current in the ring must reach the maximum oppositing is the current of the coil, so quiet force is repulsion

Consequently, the previous correct answer is b

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What is used to measure the speed of a moving vehicle along the road​
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Answer:

Speedometer

Explanation:

Speedometer

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3 years ago
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Would tap water likely freeze and boil at those exact temperatures? (temperature freezes at 0 degree celius and boils at 100 deg
Kitty [74]

No

Explanation:

Tap water will not boil and freeze at those exact temperature which are the boiling and freezing points.

O°C and 100°C are the boiling points of pure water.

Pure water is a pure substance with a definite composition made up of 2 atoms of hydrogen and 1 atom of oxygen.

Pure water boils at  100°C  and freezes at O°C ,

  • Tap water is not pure water.
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learn more:

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3 years ago
Que es una variable independiente ?
nlexa [21]

Answer:

Variable independiente

Explanation:

una variable independiente. Es una variable que está sola y no es modificada por las medidas de otras variables

7 0
3 years ago
I think 40 is the answer but i need confirmation
NNADVOKAT [17]
You’re right, bc I’m the question it says the pulley is at equilibrium
3 0
3 years ago
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A man standing in an elevator holds a spring scale with a load of 5 kg suspended from it. What would be the reading of the scale
mel-nik [20]

Answer:

3.1 kg

Explanation:

Applying,

R = m(g-a)..................... Equation 1

Where R = weight of the scale when the elevator is coming down, a = acceleration of the elevator, g = acceleration due to gravith.

From the question,

Given: m = 5 kg, a = 3.8 m/s²

Constant: g = 9.8 m/s²

Substitute these values into equation 1

R = 5(9.8-3.8)

R = 5(6)

R = 30 N

Hence the spring scale is

m' = R/g

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m' = 3.1 kg

8 0
3 years ago
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