Question

A race car starting from rest accelerates uniformly at 4.9 m/s^2. What is the car's speed after it has traveled 200 meters?

Answer 1

The equation v²=u²+2as will help with solving this equation
v is what we are trying to find
u=0
a=4.9
s=200
v²=0²+2*4.9*200
v=√(2*4.9*200)
v=√1960
v=44.3 m/s (3 sf)

Answer 2

Hello!

A race car starting from rest accelerates uniformly at a rate of 3.90 m/s² what is the cars speed after it has traveled 200 m.

We have the following data:

Vf (final velocity) = ? (in m/s)

Vi (initial velocity) = 0 m/s (accelerated from rest)

d (displacement) = 200 m

a (acceleration) = 4.90 m/s²

Since we do not need to know the time elapsed during the movement, we apply the data of the question to the Equation of Torricelli, let us see:

$V_f^2 = V_i^2 + 2*a*d$

$V_f^2 = 0^2 + 2*4.90*200$

$V_f^2 = 0 + 1960$

$V_f^2 = 1960$

$V_f = \sqrt{1960}$

$V_f = 44.27188724...$

$\boxed{\boxed{V_f \approx 44.27\:m/s}}\:\:\:\:\:\:\bf\blue{\checkmark}\bf\green{\checkmark}\bf\red{\checkmark}$

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