If F(x)= 3x/5 +3, which of the following is the inverse of f(x)?

I really really need help

nalin [4]

Answer:

here is your help

Step-by-step explanation:

VERB

helps (third person present) · helped (past tense) · helped (past participle) · helping (present participle)

make it easier for (someone) to do something by offering one's services or resources.

improve (a situation or problem); be of benefit to.

assist (someone) to move in a specified direction.

(help someone on/off with)

assist someone to put on or take off (a garment).

(help someone to)

serve someone with (food or drink).

(help oneself)

take something without permission.

(can/could not help)

cannot or could not avoid.

(can/could not help oneself)

cannot or could not stop oneself from acting in a certain way.

helps (plural noun)

the action of helping someone to do something; assistance.

a person or thing that helps.

giving assistance to a computer user in the form of displayed instructions.

used as an appeal for urgent assistance.

i hope this helps

4 0

3 years ago

Given the second order homogeneous constant coefficient equation y′′−4y′−12y=0 1) the characteristic polynomial ar2+br+c is r^2-

Vitek1552 [10]

Answer:

The initial value problem $y(x) = 4 e^{-2x} -3 e^{6 x}$

Step-by-step explanation:

Step1:-

a) Given second order homogenous constant co-efficient equation

$y^{ll} - 4y^{l}-12y=0$

Given equation in the operator form is $(D^{2} -4D-12)y=0$

Step 2:-

b) Let f(D) = $(D^{2} -4D-12)y$

Then the auxiliary equation is $(m^{2} -4m-12)=0$

Find the factors of the auxiliary equation is

$m^{2} -6m+2m-12=0$

m(m-6) + 2(m-6) =0

m+2 =0 and m-6=0

m=-2 and m=6

The roots are real and different

The general solution $y = c_{1} e^{-m_{1} x} + c_{2} e^{m_{2} x}$

the roots are $m_{1} = -2 and m_{2} = 6$

The general solution of given differential equation is

$y = c_{1} e^{-2x} + c_{2} e^{6 x}$

Step 3:-

C) Given initial conditions are y(0) =1 and y1 (0) =-26

The general solution of given differential equation is

$y(x) = c_{1} e^{-2x} + c_{2} e^{6 x}$ .....(1)

substitute x =0 and y(0) =1

$y(0) = c_{1} e^{0} + c_{2} e^{0}$

$1 = c_{1} + c_{2}$ .........(2)

Differentiating equation (1) with respective to 'x'

$y^l(x) = -2c_{1} e^{-2x} + 6c_{2} e^{6 x}$

substitute x= o and y1 (0) =-26

$-26 = -2c_{1} e^{0} + 6c_{2} e^{0}$

$-2c_{1} + 6c_{2} = -26$ .............(3)

solving (2) and (3) by using substitution method

$substitute c_{2} =1- c_{1}$ in equation (3)

$-2c_{1} + 6(1-c_{1}) = -26$

on simplification , we get

$-2c_{1} + 6(1)-6c_{1}) = -26$

$-8c_{1} = -32$

dividing by'8' we get $c_{1} =4$

substitute $c_{1} =4$ in equation $1 = c_{1} + c_{2}$

so $c_{2} = 1-4 = -3$

now substitute $c_{1} =4 and c_{2} =-3$ in general solution

$y(x) = c_{1} e^{-2x} + c_{2} e^{6 x}$

$y(x) = 4 e^{-2x} -3 e^{6 x}$

now the initial value problem

$y(x) = 4 e^{-2x} -3 e^{6 x}$

7 0

3 years ago

Please help me with the problem

Kruka [31]

Oh my gosh...thats a lot. Umm, well let's start with what the equation says. This will break it down to where it's of better understanding. What is the equation asking you to do? You have heard of the acronym "PEMDAS", correct? (Parantheses, Exponents, Multiplication, Division, Addition and Subtraction) Follow that order of operations and see what it is the equation wants done first. Solve it, basically...then we will focus on the actual question parts.

6 0

2 years ago

Read 2 more answers

Use the distributive property to find the product.

VladimirAG [237]

A Is your answer :D

W^2 + 2W + 3

4 0

3 years ago

Read 2 more answers

Sally makes a fruit drink using ⅔ of a cup of orange juice for every ¼ of a cup of pineapple juice. How many cups of orange juic

Shkiper50 [21]

Answer:

5 1/3

Step-by-step explanation:

Set up ratio.

2/3 cup orange juice X 2 cups pineapple juice

———————————-

1/4 cup pineapple juice

first multiply numerator : 2/3 x 2 = 4/3

and divide by denominator

(4/3)/(1/4). Keep the first. Change the sign to multiplication and Flip the second fraction.

4/3 x 4/1 = 16/3

change to proper fraction : 16/3 = 5 1/3 cups

7 0

3 years ago