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anastassius [24]
2 years ago
8

What do you think would happen to the boiling point of water if you were to cook pasta near the Dead Sea in Israel, which is 1,2

96 feet below sea level? Would it take a longer or shorter time than cooking the spaghetti in London, England, which is at sea level? Does the pot of boiling water in Israel contain more or less heat than the pot in London?
Physics
2 answers:
ad-work [718]2 years ago
6 0
Kejssjannaksjs ksnsjsna
mina [271]2 years ago
5 0

Answer:

I think it will be the same.

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A cyclist is riding a bicycle at a speed of 22 mph on a horizontal road. The distance between the axles is 42 in., and the mass
stealth61 [152]

Answer:

The shortest distance is  S = 24.86 ft

Explanation:

The free body diagram of this question is shown on the first uploaded image

From the question we are told that

   The speed of the bicycle is v_b = 22\ mph = 22 * \frac{5280}{3600}   =  32.26 ft/s

     The distance between the axial is  d = 42 \ in

The mass center of the cyclist and the bicycle is m_c = 26 \ in  behind the front axle

The mass center of the cyclist and the bicycle is m_h = 40 \ in above the ground

   For the bicycle not to be thrown over the

     Momentum about the back wheel must be zero so

                \sum _B = 0

=>             mg (26) = ma(40)

=>             a = \frac{26}{40} g

Here  g = 32.2 ft/s^2

     So     a =  \frac{26}{40} (32.2)

             a =  20.93 ft/s^2

Apply the equation of motion to this motion we have

       v^2 = u^2 + 2as

 Where  u = 32.26 ft /s

             and v = 0 since the bicycle is coming to a stop

        v^2 = (32.26)^2 - 2(20.93) S

=>      S = 24.86 ft        

                 

5 0
2 years ago
An object of known mass M with speed v0 travels toward a wall. The object collides with it and bounces away from the wall in the
Bingel [31]

Neither side of the equation may be used because there are too many unknown quantities before, during, and after the collision

Explanation:

The impulse theorem states that the change in momentum of an object is equal to the impulse, which is the product between the average force applied and the duration of the collision:

\Delta p = F \Delta t

where

\Delta p is the change in momentum

F is the average force

\Delta t is the duration of the collision

In this problem, neither side of the equation can be used to measure the change in momentum. In fact:

- The change in momentum (left side) is given by

\Delta p = m(v-u)

where

m is the mass of the object

u is the initial velocity

v is the final velocity

Here the final velocity is not known, so it's not possible to use this side of the equation

- The impulse (right side) is given by

F\Delta t

here the average force is known, however the duration of the collision is not known, so it's not possible to use this side of the equation.

Learn more about momentum:

brainly.com/question/9484203

#LearnwithBrainly

3 0
3 years ago
The current in a toaster is 20 amps, and its voltage is 200 volts. What is the resistance in the toaster?
alukav5142 [94]
<span>Ohm's law deals with the relation between voltage and current in an ideal conductor. It states that: Potential difference across a conductor is proportional to the current that pass through it. It is expressed as V=IR. 

V = IR
200 = 20R
R = 10 ohms</span>
8 0
2 years ago
Read 2 more answers
A strontium vapor laser beam is reflected from the surface of a CD onto a wall. The brightest spot is the reflected beam at an a
sladkih [1.3K]

Answer:

d=1.29*10^{-6}m

Explanation:

From the question we are told that:

Distance of wall from CD D=1.4

Second bright fringe y_2= 0.803 m

Let

Strontium vapor laser has a wavelength \lambda= 431 nm=>431 *10^{-9}m

Generally the equation for Interference is mathematically given by

y=frac{n*\lambda*D}{d}

Where

d=\frac{n*\lambda*D}{y}

d=\frac{2*431 *10^{-9}m*1.4}{0.803}

d=1.29*10^{-6}m

8 0
2 years ago
A particle in uniform circular motion requires a net force acting in what direction?
mel-nik [20]
The net force will point towards the acceleration of the object, as supported by Newton's second law.
6 0
3 years ago
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