resolve the position vector A of thd car (measured from fixed point O) into components parallel to OB and OC

1 answer:

7 0

Catalysts are used in the oil industry to increase octane ratings in gasoline. Octane ratings tell how much fuel has to be compressed to promote better fuel ignition in some cars. The catalytic effect that would be most beneficial for the oil industry is that more products can be formed from a given amount of material.

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Which statement is true about the reaction shown by this chemical equation?

KatRina [158]

Answer:

it's C endothermic

Explanation:

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2 years ago

Scientists use laser range-finding to measure the distance to the moon with great accuracy. A brief laser pulse is fired at the

Fofino [41]

Answer:

d = 2,042 10-3 m

Explanation:

The laser diffracts in the circular slit, so the process equation is

d sin θ= m λ

The first diffraction minimum occurs for m = 1

We can use trigonometry in the mirror

tan θ = Y / L

Where L is the distance from the Moon to Earth

Since the angle is extremely small

tan θ = sin θ / cos θ

Cos θ = 1

tant θ = sin θ = y / L

We replace

d y / L = λ

d = λ L / y

Let's calculate

d = 532 10⁻⁹ 3.84 10⁶/1 10³

d = 2,042 10-3 m

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2 years ago

How many kilocalories are generated when the brakes are used to bring a 1200-kg car to rest from a speed of 95 km/h ? 1 kcal = 4

timofeeve [1]

<span>Answer: 1st, identify the givens and the unknown - this will give you parameter of what concept and formula are you going to use. Given: m= 1200kg v initial = 95km/hr v final = 0 2nd, focus on the units - in most cases units speak for the concept the unit of the unknown is kcal, thus its the unit of energy or work so, W = ? 3rd, provide the appropriate formula - give formula or equation that the given and the unknown are present since W = delta K.E =delta P.E W= 0.5m( vf^2 - vi^2) ---> best formula 4th, Substitute the given to the formula since 1 Joule = 1Nm 1N = 1kgms^-2 1cal = 4.19 J we express first 95 km/hr to m/s 95km/hr x 1000m/1km x 1hr/3600sec = 26.39 m/sec W= 0.5(1200kg)[(0^2- (26.39m/sec)^2] W=600 kg(0 - 696.43m^2/s^2) W=600kg(-696.43m^2/s^2) W=417859.3Nm or 417859.3 J W = 417859.3 J x 1 cal /4.19 J W = 99,727.7 cal or 99.728 kcal</span>

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2 years ago

A truck moving at 7.0 meters per second accelerates to a speed of 15.0 meters per second within a time of 1.5 seconds. Calculate

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Answer:

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SO GIRLS PLEASE LOVE ME!

Explanation:

I WANT TO BE HANDSOME AND I WANT TO BE HEARTTHROB!

SO GIRLS PLEASE LOVE ME!

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2 years ago