Ask question

Ask question

All categories

3 years ago

13

resolve the position vector A of thd car (measured from fixed point O) into components parallel to OB and OC

1 answer:

forsale [732]3 years ago

7 0

Catalysts are used in the oil industry to increase octane ratings in gasoline. Octane ratings tell how much fuel has to be compressed to promote better fuel ignition in some cars. The catalytic effect that would be most beneficial for the oil industry is that more products can be formed from a given amount of material.

You might be interested in

Select the correct answer from each drop-down menu.

amid [387]

Answer:

Rust is a compound. What makes iron rust is its reaction with oxygen and moisture in the air.

4 0

3 years ago

Besides the force due to gravity or g, what else determines the period of a pendulum?

pochemuha

Length of the cord..........................................................

6 0

3 years ago

Read 2 more answers

A girl whose weight is 220-N hangs from

DENIUS [597]

Answer: 55n

Explanation:

3 0

3 years ago

On a typical clear day, the atmospheric electric field points downward and has a magnitude of approximately 103 N/C. Compare the

Nina [5.8K]

Answer:

a) FE = 0.764FG

b) a = 2.30 m/s^2

Explanation:

a) To compare the gravitational and electric force over the particle you calculate the following ratio:

$\frac{F_E}{F_G}=\frac{qE}{mg}$ (1)

FE: electric force

FG: gravitational force

q: charge of the particle = 1.6*10^-19 C

g: gravitational acceleration = 9.8 m/s^2

E: electric field = 103N/C

m: mass of the particle = 2.2*10^-15 g = 2.2*10^-18 kg

You replace the values of all parameters in the equation (1):

$\frac{F_E}{F_G}=\frac{(1.6*10^{-19}C)(103N/C)}{(2.2*10^{-18}kg)(9.8m/s^2)}\\\\\frac{F_E}{F_G}=0.764$

Then, the gravitational force is 0.764 times the electric force on the particle

b)

The acceleration of the particle is obtained by using the second Newton law:

$F_E-F_G=ma\\\\a=\frac{qE-mg}{m}$

you replace the values of all variables:

$a=\frac{(1.6*10^{-19}C)(103N/C)-(2.2*10^{-18}kg)(9.8m/s^2)}{2.2*10^{-18}kg}\\\\a=-2.30\frac{m}{s^2}$

hence, the acceleration of the particle is 2.30m/s^2, the minus sign means that the particle moves downward.

7 0

3 years ago

A car driver traveling at a speed of 108km per hour ,sees a traffic light and stopped after travelling for 20seconds .Find the a

navik [9.2K]

Answer:

– 2.5 m/s²

Explanation:

We have,

• Initial velocity, u = 180 km/h = 50 m/s

• Final velocity, v = 0 m/s (it stops)

• Time taken, t = 20 seconds

We have to find acceleration, a.

$\longrightarrow$ a = (v ― u)/t

$\longrightarrow$ a = (0 – 50)/20 m/s²

$\longrightarrow$ a = –50/20 m/s²

$\longrightarrow$ a = – 5/2 m/s²

$\longrightarrow$ a = – 2.5 m/s² (Velocity is decreasing) [Answer]

6 0

3 years ago