D+n=25 subtract d from both sides *(if your wondering what d and n are it stands for Dimes and Nickels)* n=25-d
0.10d+0.05= 1.85
0.10d+0.05(25-d)= 1.85
0.10d+1.25-0.05d= 1.85
0.05d = 0.60
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My answer: He has 12 dimes (d=12) and 25-12=13 so 13 nickels.. Hope this helps! :)
Z-m=z+bx
z-m-z=z+bx-z
-m=bx
bx=-m
bx/b=-m/b; b=0
x=-m/b; b=0
9514 1404 393
Answer:
3362 ft²
Step-by-step explanation:
As we saw in brainly.com/question/22284853, the long side of the area will be half the length of the fence: 82 feet. The remaining two sides will be 41 feet each, so the largest area that can be enclosed is ...
A = LW
A = (82 ft)(41 ft) = 3362 ft²
<h3>given:</h3>
radius= 4 cm
<h3>to find:</h3>
the area and the diameter of the circle.
<h3>solution:</h3><h3>diameter:</h3>
![d = 2r](https://tex.z-dn.net/?f=d%20%3D%202r)
![d = 2 \times 4](https://tex.z-dn.net/?f=d%20%3D%202%20%5Ctimes%204)
![d = 8 \: cm](https://tex.z-dn.net/?f=d%20%3D%208%20%5C%3A%20cm)
<u>therefore</u><u>,</u><u> </u><u>the</u><u> </u><u>diameter</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>circle</u><u> </u><u>is</u><u> </u><u>8</u><u> </u><u>centimeters</u><u>.</u>
<h3>area:</h3>
![a = \pi {r}^{2}](https://tex.z-dn.net/?f=a%20%3D%20%5Cpi%20%7Br%7D%5E%7B2%7D%20)
![a = \pi \times {4}^{2}](https://tex.z-dn.net/?f=a%20%3D%20%5Cpi%20%5Ctimes%20%20%7B4%7D%5E%7B2%7D%20)
![a = 50.26548 \: {cm}^{2}](https://tex.z-dn.net/?f=a%20%3D%2050.26548%20%5C%3A%20%20%7Bcm%7D%5E%7B2%7D%20)
![a = 50.27 \: {cm}^{2}](https://tex.z-dn.net/?f=a%20%3D%2050.27%20%5C%3A%20%20%7Bcm%7D%5E%7B2%7D%20)
<u>hence</u><u>,</u><u> </u><u>the</u><u> </u><u>area</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>circle</u><u> </u><u>is</u><u> </u><u>50.27</u><u> </u><u>square</u><u> </u><u>centimeters</u><u>.</u>
Answer:
y=4/x^3
Step-by-step explanation: