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2 years ago

2/3 ( 1/5x + 6y) + 2/5 ( 1/2x + 1/3y)

Mathematics

2 answers:

svetlana [45]2 years ago

6 0

Answer:

use phototmath I promise it will help u even if I dont give u the answer

Ipatiy [6.2K]2 years ago

6 0

Answer:

If you look it up, it will tell u the answer

Step-by-step explanation:

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whitch integer is described by the following? The absolute value is 3 and the number is to the left of 0 on the number line

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-3 because absolute value is basically any number between two lines like this l -3 l the absolute value of -3 is three.

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3 years ago

A recipe for fluid ounces of milk. What is the amount of milk called for in cups

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There are 8 fluid ounces in one cup

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3 years ago

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How to solve for X in the triangle

Vikentia [17]

Answer:

22.6

Step-by-step explanation:

a^2+b^2=c^2

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2 years ago

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Una maquina que fabrica tornillos produce un 3% de piezas defectuosas. Si hoy se han apartado 51 tornillos defectuosos cuantos t

grin007 [14]

Answer:

1700 tornillos

Step-by-step explanation:

Dado que la máquina produce un 3% de tornillos defectuosos en un día. Produjo 51 tornillos defectuosos en un día.

Deje que el número total de tornillos producidos ese día sea x

Por lo tanto;

3% de x = 51

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7 0

2 years ago

Simplify. Evaluate the numerical bases. 3^2 b^2 c^-4 *3^-1 b^-5 c^7

photoshop1234 [79]

Hope I can be of assistance!

$3^2b^2c^{-4}\cdot \:3^{-1}b^{-5}c^7 \ \textgreater \ \mathrm{Apply\:exponent\:rule}:\ \:a^b\cdot \:a^c=a^{b+c}$
$3^{-1}\cdot \:3^2=\:3^{2-1}=\:3^1=\:3 \ \textgreater \ 3b^{-5}b^2c^{-4}c^7$

$\mathrm{Apply\:exponent\:rule}: \:a^b\cdot \:a^c=a^{b+c} \ \textgreater \ b^{-5}b^2=\:b^{2-5}=\:b^{-3}$
$3b^{-3}c^{-4}c^7$

$\mathrm{Apply\:exponent\:rule}: \:a^b\cdot \:a^c=a^{b+c} \ \textgreater \ c^{-4}c^7=\:c^{-4+7}=\:c^3$
$3b^{-3}c^3$

$\mathrm{Apply\:exponent\:rule}: \:a^{-b}=\frac{1}{a^b} \ \textgreater \ b^{-3}=\frac{1}{b^3} \ \textgreater \ 3\cdot \frac{1}{b^3}c^3$

$\mathrm{Multiply\:fractions}: \:a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c} \ \textgreater \ \frac{1\cdot \:3c^3}{b^3}$

Finally
$\mathrm{Apply\:rule}\:1\cdot \:a=a \ \textgreater \ \frac{3c^3}{b^3}$

Hope this helps!

8 0

3 years ago