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3 years ago

A.Who was the first english mathematician who first used the modern symbol of equality in 1557?

Mathematics

1 answer:

liberstina [14]3 years ago

8 0

Answer:

Robert Recorde.

Step-by-step explanation:

Robert Recorde was a Welsh known for vast knowledge and experience in the field of mathematics and physics. He was born in Tenby, Pembrokeshire, Wales during the Medieval period (c. 1512).

Robert Recorde was famously known for his work in the field of mathematics and most especially, the invention of the equal to (=) sign. He introduced it in his book titled "The Whetstone of Witte."

<em>Hence, Robert Recorde was the first english mathematician who first used the modern symbol of equality in 1557. </em>

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What 2 things are recommended in order for you to have a neat graph

Oksana_A [137]

Answer:

use a ruler

buy a graph

Step-by-step explanation:

Not the best answer tho... becuase this useless Mod deleted all my answers randomly

6 0

3 years ago

Which are sums of perfect cubes? Check all that apply. 8x6 27 x9 1 81x3 16x6 x6 x3 27x9 x12 9x3 27x9.

Black_prince [1.1K]

The equations which are sums of perfect cubes are as follows;

$\rm 8x^6+27x^9+1$

$\rm x^6+x^3$

$\rm 27x^9+x^{12}$

<h3>Perfect cubes;</h3>

Perfect cubes are the numbers that are the triple product of the same number.

We have to determine

Which are sums of perfect cubes?

1. The given equation is $\rm 8x^6+27x^9+1$ .

The equation can be written as;

$\rm 8x^6+27x^9+1\\\\2^3(x^2)^3+3^3(x^3)^3+1^3$

All the terms in the expression are can be represented as perfect cubes.

2. The given equation is $\rm 81x^3+16x^6$ .

The equation can be written as;

$\rm 81x^3+16x^6\\\\9^2x^3+4^2(x^2)3$

In this, all the terms are not perfect cubes, some of them are squares.

3. The given equation is $\rm x^6+x^3$ .

The equation can be written as;

$\rm x^6+x^3\\\\(x^2)^3+x^3$

All the terms in the expression are perfect cubes.

4. The given equation is $\rm 27x^9+x^{12}$ .

The equation can be written as;

$\rm 27x^9+x^{12}\\\\3^3(x^3)^3+(x^4)^3$

All the terms in the expression are perfect cubes.

5. The given equation is $\rm 9x^3+27x^9$ .

The equation can be written as;

$\rm 9x^3+27x^9\\\\3^2x^3+3^3(x^3)^3$

In this, all the terms are not perfect cubes, some of them are squares too.

To know more about perfect cubes click the link given below.

brainly.com/question/4701925

5 0

2 years ago

Read 2 more answers

A man travels from town x to town y at an average rate of 60 mph and returns at an average rate of 50 mph. He takes a 1/2 hour l

Georgia [21]

D/60 + D/50 = 2D/55 - 1/2

find common denominator ( 3300)

3300/60 = 55

3300/50 = 66

3300/55=60

so then you get 55D +66D= 60(2D)-1650

121D=120D-1650

D=1650 miles

check

1650/60 =27.5, 1650/50 = 33, 27.5 + 33 = 60.5 hours total

1650/55 = 30, 30 x 2 = 60

60.5-60 = 0.5 longer

so distance = 1650 miles

3 0

3 years ago

Give an equation that goes through the line 3,-1 that is parallel to 6x-5

allochka39001 [22]

Lines that are parallel have the same slope, and the given line (y = 6x - 5) has a slope of 6; we are looking for a line with a slope of 6.
To form an equation for a line, you need to know the y-intercept (the point at which the line intersects the y-axis). The first step to finding the y-intercept is to plot the given point. After you've done that, count six units up (this is our slope) and one to the right; plot the point. Lastly, draw the line by connecting the points and see where the line intersects the y-axis.
My graph shows that the line intersects the y-axis at -17. All that's left now is to put our information together into an equation. I'm assuming the problem wants the equation in slope-intercept form; slope-intercept form is y = mx + b where m is the slope and b is the y-intercept, so it would look like this:
y = 6x -17

Hope this helps.

8 0

3 years ago

Read 2 more answers

Find the greatest common factor

Anuta_ua [19.1K]

Answer:

$1$

Step-by-step explanation:

$7w^2$ and $9m^3$ does not have any common factor except for $1$

4 0

3 years ago