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2 years ago

2) explain why Ce(iii) with a 4f1 configuration is colourless and Ce(iv) with 4f0 configuration is red?

Chemistry

1 answer:

kykrilka [37]2 years ago

5 0

Answer:

Don't know don't know don't know

Explanation:

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3 years ago

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3 years ago

A closed system initially containing 1×10^-3 hydrogen 2×10^-3M iodine at 448 degree Celsius and is allowed to reach equilibrium.

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Answer:

Kc = 50.5

Explanation:

We determine the reaction:

H₂ + I₂ ⇄ 2HI

Initially we have 0.001 molesof H₂

and 0.002 moles of I₂

If we have produced 0.00187 moles of HI in the equilibrium we have to know, how many moles of I₂ and H₂, have reacted.

H₂ + I₂ ⇄ 2HI

In: 0.001 0.002 -

R: x x 2x

Eq: 0.001-x 0.002-x 0.00187

x = 0.00187/2 = 9.35×10⁻⁴ moles that have reacted

So in the equilibrium we have:

0.001 - 9.35×10⁻⁴ = 6.5×10⁻⁵ moles of H₂

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Expression for Kc is = (HI)² / (H₂) . (I₂)

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2 years ago

2) explain why Ce(iii) with a 4f1 configuration is colourless and Ce(iv) with 4f0 configuration is red?​

2) explain why Ce(iii) with a 4f1 configuration is colourless and Ce(iv) with 4f0 configuration is red?