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mrs_skeptik [129]
2 years ago
13

Can someone help me with this question

Mathematics
1 answer:
Vera_Pavlovna [14]2 years ago
4 0

Answer:

200 kids

Step-by-step explanation:

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Please help. i will brainlist you
Lostsunrise [7]

Answer:

first question:

range-22

IQR-13

second question:

range-26

IQR-15.5

I hope this helped bestie!

7 0
3 years ago
Which radical expressions are equivalent to 7 5/4
Troyanec [42]

Answer: = √(22·2) (x2·x) y2 (z4. z) EXAMPLE Put 3√24 x6 y5 z10 in standard form. EXAMPLE Put 3√− 2 x11 y4 in standard form. EXAMPLE Put 4√64 x4 y10 in standard form. DEFINITION Radical expressions are said to be similar when they have the same radical index and the same radicand. EXAMPLES 1. The redial expressions 3 √2 and 5 √2 are similar. 2.

Step-by-step explanation:

Yw and mark me brainiest

4 0
2 years ago
Read 2 more answers
Complete the square to make a perfect square trinomial. Then, write the result as a binomial squared. n^2-4n/3
ololo11 [35]

Answer:

(n- 2/3)²

Step-by-step explanation:

  • <em>Perfect square trinomial is: </em><em>a²+2ab+b²= (a+b)²</em>

We have:

  • n² - 4n/3

It can be put as:

  • n² -2×n×2/3

Here we consider n = a and -2/3 = b, then

  • b²= (-2/3)²= 4/9

Now we add 4/9 to a given binomial to make it perfect square:

  • n² - 2×n×3/2 + 4/9= (n- 2/3)²

So, added 4/9 and got a perfect square (n- 2/3)²

7 0
3 years ago
Use the table below to answer this question:
andrew11 [14]
(y_final-y_start)/(x_final-x_start) always! :) that easy

(-6-2)/(2-0) = -4

You probably know that if the interval was pretty small, between 0 and 0.0001, it would take you to the concept of slope and derivatives, but average change is just ignoring anything in between x=0, and x=2 (it could go up/down million times, and still the answer would be -4)

hope it helps
3 0
3 years ago
Match each series with the equivalent series written in sigma notation
PIT_PIT [208]

Answer:

3 + 12 + 48 + 192 + 768 = \sum\limits^4_{n=0} 3 * 4^n

4 + 32 + 256 + 2048 + 16384 = \sum\limits^4_{n=0} 4 * 8^n

2 + 6 + 18 + 54 + 162 = \sum\limits^4_{n=0} 2* 3^n

3 + 15 + 75 + 375 + 1875 = \sum\limits^4_{n=0} 3* 5^n

Step-by-step explanation:

Given

See attachment for complete question

Required

Match equivalent expressions

Solving (a):

3 + 12 + 48 + 192 + 768

The expression can be written as:

3 \to 3*4^{0 --- 0

12 \to 3 * 4^{1 ---- 1

48 \to 3 * 4^{2 --- 2

192 \to 3 * 4^{3 ---- 3

768 \to 3 * 4^{4 ---- 4

For the nth term, the expression is:

Term = 3 * 4^{n ---- n

So, the summation is:

3 + 12 + 48 + 192 + 768 = \sum\limits^4_{n=0} 3 * 4^n

Solving (b):

4 + 32 + 256 + 2048 + 16384

The expression can be written as:

4 \to 4 * 8^0 --- 0

32 \to 4 * 8^1 ---- 1

256 \to 4 * 8^2 --- 2

2048 \to 4 * 8^3 ---- 3

16384 \to 4 * 8^4 ---- 4

For the nth term, the expression is:

Term \to 4 * 8^n ---- n

So, the summation is:

4 + 32 + 256 + 2048 + 16384 = \sum\limits^4_{n=0} 4 * 8^n

Solving (c):

2 + 6 + 18 + 54 + 162

The expression can be written as:

2 \to 2 * 3^0 --- 0

6 \to 2 * 3^1 ---- 1

18 \to 2 * 3^2 --- 2

54 \to 2 * 3^3 ---- 3

162 \to 2 * 3^4 ---- 4

For the nth term, the expression is:

Term \to 2 * 3^n ---- n

So, the summation is:

2 + 6 + 18 + 54 + 162 = \sum\limits^4_{n=0} 2* 3^n

Solving (d):

3 + 15 + 75 + 375 + 1875

The expression can be written as:

3 \to 3 * 5^0 --- 0

15 \to 3 * 5^1 ---- 1

75 \to 3 * 5^2 --- 2

375 \to 3 * 5^3 ---- 3

1875 \to 3 * 5^4 ---- 4

For the nth term, the expression is:

Term \to 3 * 5^n ---- n

So, the summation is:

3 + 15 + 75 + 375 + 1875 = \sum\limits^4_{n=0} 3* 5^n

5 0
2 years ago
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