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3 years ago

Which point lies on the graph of y=2(1/2^x?

Mathematics

1 answer:

qaws [65]3 years ago

8 0

Answer:

(0,0)

Step-by-step explanation:

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Answer this question please and thank you

Fiesta28 [93]

Answer:

7/8 to the 7th power

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Simplify:<br> 3 [23 + (4 – 2)3 – (6 - 2)2]<br> A. 3<br><br> B. 12<br> D. 24<br><br> E-3

diamong [38]

Answer:63

Step-by-step explanation:

4 0

3 years ago

Another question for math. ill give mad points, the question is in attachment

yulyashka [42]

For this case we have the following points:
y = (- 2, 5)
z = (1, 3)
Therefore, the vector yz is given by:
yz = z - y = (1, 3) - (-2, 5)
yz = ((1 - (- 2)), (3-5))
yz = ((1 + 2), -2)
yz = (3, -2)
Then, the magnitude is given by:
lyzl = root ((3) ^ 2 + (-2) ^ 2)
lyzl = root (9 + 4)
lyzl = root (13)
Answer:
yz = (3, -2)
lyzl = root (13)
option A

5 0

3 years ago

1.3.12

kondaur [170]

Answer:

Step-by-step explanation:

The formula for calculating the midpoint of two coordinates is expressed as shown;

M(X, Y) = [(x1+x2)/2, (y1+y2)/2]

Given the midpoint of ST to be ((6, -2) and one endpoint T is (0,2), according to expression above;

X = (x1+x2)/2

Y = (y1+y2)/2

From the coordinates, X = 6, Y = -2, x1 = 0 and y1 = 2, to get x2 and y2;

X = (x1+x2)/2

6 = (0+x2)/2

cross multiply

12 = 0+x2

x2 = 12-0

x2 = 12

For 2;

Y = (y1+y2)/2

-2 = (2+y2)/2

cross multiply

-4 = 2+y2

y2 = -4-2

y2 = -6

<em>Hence the other endpoint S(x2, y2) is (12, -6)</em>

3 0

3 years ago

The admission fee is $1.50 for children and $4.00 for adults. If 2700 people enter and $7800 is collected how many children and

mash [69]

Number of children attended is 1200 and number of adults attended is 1500

<h3><u>Solution:</u></h3>

Given that,

Admission fee for each children = $ 1.50

Admission fee for each adult = $ 4.00

Let "c" be the number of children attended

Let "a" be the number of adults attended

Given that 2700 people enter and $7800 is collected

Number of children attended + number of adults attended = 2700

c + a = 2700 -------- eqn 1

Also given that $7800 is collected

Number of children attended x Admission fee for each children + number of adults attended x Admission fee for each adult = 7800

$c \times 1.50 + a \times 4 = 7800$

1.5c + 4a = 7800 -------- eqn 2

Let us solve eqn 1 and eqn 2 to find values of "a" and "c"

From eqn1,

a = 2700 - c ----- eqn 3

Substitute eqn 3 in eqn 2

1.5c + 4(2700 - c) = 7800

1.5c + 10800 - 4c = 7800

-2.5c = -3000

c = 1200

Therefore from eqn 3,

a = 2700 - 1200

a = 1500

Therefore number of children attended = c = 1200

number of adults attended = a = 1500

3 0

3 years ago