Answer:
Tantalium is a Transition metal.
Osmium is a Transition metal.
Thorium is radioactive Metal.
Answer:
pOH = -log₁₀ [OH-]
pH = 14 - pOH
Explanation:
First of all, calculate the value of pOH from the hydroxide concentration do this using the equation below;
pOH = -log₁₀ [OH-]
After obtaining the pOH, calculate pH using the equation below:
pH + pOH = 14
pH = 14 - pOH
Answer:
4.55 mol of C₂H₂
Explanation:
Let's verify the reaction:
CaC₂ + 2H₂O → C₂H₂ + Ca(OH)₂
Ratio is 1:1, so 1 mol of calcium carbide will produce 1 mol of acetylene.
4.55 mol of CaC₂ will make the same amount of C₂H₂
Answer:
Weight % of NH₃ in the aqueous waste = 2.001 %
Explanation:
The chemical equation for the reaction
Moles of HCl = Molarity × Volume
= 0.1039 × 31.89 mL × 
= 0.0033 mole
Total mass of original sample = 25.888 g + 73.464 g
= 99.352 g
Total HCl taken for assay = 
= 0.1083 g
Moles of NH₃ = 
= 0.03047 moles
Mass of NH₃ = number of moles × molar mass
Mass of NH₃ = 0.03047 moles × 17 g
Mass of NH₃ = 0.51799
Weight % of NH₃ = 
%
Weight % of NH₃ in the aqueous waste = 2.001 %
We will assume that the question is discussing 1.000 atm of N₂ initially. The question is discussing diffusion rates of two gases and asks us to identify the species. We can use Graham's Law to attempt this problem with the following formula:
Rate₁/Rate₂ = sqrt(M₂/M₁)
We are told that the N₂ is 3.55 times as fast as the unknown species, so rate 1 = 3.55 and rate 2 = 1. We know the molecular weight of N₂ as 28 g/mol. Now we can use the equation above to solve for the molecular weight of the unknown, M₂:
3.55/1 = sqrt(M2/28)
(3.55)² = M₂/28
M₂ = 28 (3.55)₂
M₂ = 353 g/mol
The unknown compound has a molecular mass of roughly 353 g/mol and this is very close to the molecular mass of UF₆ which is 352.02 g/mol. Therefore, it is likely that the unknown gas is UF₆.
