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Orlov [11]
4 years ago
8

If a mixture of gases contained 78% nitrogen at a pressure of and 22% carbon dioxide at , what is the total pressure of the syst

em? 1,329 atm 17.5 cm hg 639 torr 1.75 atm none of these
Chemistry
1 answer:
Naddika [18.5K]4 years ago
4 0
The pressures given are the partical pressures of the two gases.

The law of Dalton or of the partial pressures states that the total pressure of a mixture of gases is equal to the sum of the pressures of all the gases.

So, in this case:

Total pressure = pressure of nitrogen + pressure of carbon dioxyde.

Of course both terms must be in the same units.

i have found that the pressures for this problem are:

Pressure of nitrogen = 984 torr

Pressure of carbon dioxyde = 345 torr

Total pressure = 984 torr + 345 torr = 1329 torr.

Now convert to atm: 1 atm = 760 torr

=> 1329 torr * 1 atm / 760 torr = 1.74868 atm ≈ 1.75 atm

Answer: 1.75 atm

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The solubility of magnesium phosphate at a given temperature is 0.173 g/L. Calculate the Ksp at this temperature. After you calc
jek_recluse [69]

Answer: K_{sp}=1.25\times 10^{-14}

pK_{sp}=13.90

Explanation:

Solubility product is defined as the equilibrium constant in which a solid ionic compound is dissolved to produce its ions in solution. It is represented as K_{sp}  

The equation for the ionization of magnesium phosphate is given as:

Mg_3(PO_4)_2\rightarrow 3Mg^{2+}+2PO_4^{3-}

 When the solubility of Mg_3(PO_4)_2 is S moles/liter, then the solubility of Mg^{2+} will be 3S moles\liter and solubility of PO_4^{3-} will be 2S moles/liter.

Thus S = 0.173 g/L or \frac{0.173g/L}{262.8g/mol}=0.00065mol/L

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5 0
3 years ago
Zn + I2 ---&gt; Znl2<br> Determine the theoretical yield of the product if 2g of Zn is used
egoroff_w [7]

Answer:

Mass = 9.58 g

Explanation:

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Mass of Zn = 2g

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Zn + I₂       →     ZnI₂

Number of moles of Zn:

Number of moles = mass/molar mass

Number of moles = 2g / 65.38 g/mol

Number of moles = 0.03 mol

Now we will compare the moles of Zn and ZnI₂.

                   Zn           :          ZnI₂

                    1             :           1

                  0.03        :         0.03

Mass of ZnI₂:

Mass = number of moles × molar mass

Mass = 0.03 mol × 319.22 g/mol

Mass = 9.58 g

4 0
3 years ago
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