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Orlov [11]
4 years ago
8

If a mixture of gases contained 78% nitrogen at a pressure of and 22% carbon dioxide at , what is the total pressure of the syst

em? 1,329 atm 17.5 cm hg 639 torr 1.75 atm none of these
Chemistry
1 answer:
Naddika [18.5K]4 years ago
4 0
The pressures given are the partical pressures of the two gases.

The law of Dalton or of the partial pressures states that the total pressure of a mixture of gases is equal to the sum of the pressures of all the gases.

So, in this case:

Total pressure = pressure of nitrogen + pressure of carbon dioxyde.

Of course both terms must be in the same units.

i have found that the pressures for this problem are:

Pressure of nitrogen = 984 torr

Pressure of carbon dioxyde = 345 torr

Total pressure = 984 torr + 345 torr = 1329 torr.

Now convert to atm: 1 atm = 760 torr

=> 1329 torr * 1 atm / 760 torr = 1.74868 atm ≈ 1.75 atm

Answer: 1.75 atm

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<span>_Fe + _ H2SO4 --> _Fe2 (SO4)3 + _H2

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Now let's start balancing. As a prerequisite, you must keep in mind that we can only add numbers in front of whole molecules, whereas it is not scientifically correct to change the little numbers (we could have two sulphuric acids instead of one, represented by 2H2SO4 (where the 2 would be a normal-sized 2 when written down), but we couldn't change H2SO4 to H3SO4).

The iron atoms can be balanced by having two iron atoms on the left-hand side instead of one:

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This is the balanced symbol equation for the displacement of hydrogen with iron in sulphuric acid.

For question b, I will just show you the stages without the explanation (I take the 3 before B2 to be a mistake, because it makes no sense to use 3B2Br6 when B2Br6 balances fine):

<span>B2 Br6 + _ HNO 3 -->_B(NO3)3 +_HBr
B2Br6 + _HNO3 --> _B(NO3)3 + 6HBr
B2Br6 + 6HNO3 --> _B(NO3)3 + 6HBr</span>
<span><span>B2Br6 + 6HNO3 --> 2B(NO3)3 + 6HBr</span>

Hopefully you can get the others now yourself. I hope this helped
</span>


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