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Lunna [17]
3 years ago
14

Ta, Os, Th are from metal?

Chemistry
1 answer:
Alex787 [66]3 years ago
6 0

Answer:

Tantalium is a Transition metal.

Osmium is a Transition metal.

Thorium is radioactive Metal.

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a 25 ml volume of a sodium hydroxide solution requires 19.6 mL of a 0.189 M HCl acid for neutralization. A 10 mL volume of phosp
Drupady [299]

Answer: 0.172 M

Explanation:

a) To calculate theconcentration of base, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HCl

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=1\\M_1=0.189M\\V_1=19.6mL\\n_2=1\\M_2=?\\V_2=25mL

Putting values in above equation, we get:

1\times 0.189\times 19.6=1\times M_2\times 25\\\\M_2=0.148

b) To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_3PO_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=3\\M_1=?\\V_1=10mL\\n_2=1\\M_2=0.148\\V_2=34.9mL

Putting values in above equation, we get:

3\times M_1\times 10=1\times 0.148\times 34.9\\\\M_1=0.172M

The concentration of the phosphoric acid solution is 1.172 M

3 0
3 years ago
Pls help if you only know the correct answer! Thanks! :)
Aleksandr [31]

18. the blank should be "CO_{2}"

19. the question seems to be answered.

20. CH_{3}

3 0
2 years ago
Calculate the mass of water produced by the metabolism of 49.0 g of glucose (C6H12O6). C6H12O6 + 6O2 → 6CO2 + 6H2O
aivan3 [116]
I will mark brainlist please help

1) what is the subject of a sentence?

• the verb

• tells who or what the sentence is about

• the action in the sentence


2) What is the predicate of a sentence?

• who the sentence is about?

• tells what the subject is or does


3) What is the PREDICATE in this sentence.

- Mrs. Shaffer is crazy


• Mrs. Shaffer

• is

• is crazy

• Shaffer is crazy


4) what is the predicate of this sentence.

- Friday is the best day of the week

• Friday

• is the best day of the week


5) What is the subject of this sentence?

- The turtle is swimming in the ocean

• the turtle

• is swimming in the ocean


6) What is the the complete predicate of this sentence?

- The class studied whales.

• class

• the class

• whales

• studied whales


7) What is the predicate in the sentence

- She drank her whole glass of milk

• she

• milk

• drank her whole glass of milk

• drank milk


8) what is the subject in the sentence?

- The music class attended the opera.

• the music class

• attended

• music


9) identify the complete subject.

- Susan and Kay went swimming.

• went swimming

• Susan and Kay

• went


10) identify the COMPLETE predicate

- Tina and her friends went to the movies

• Tina

• her friends

• to the movies

• went to the movies


11) identify the SIMPLE PREDICATE PART.

- Tina and her friends went to the movies

• Tina

• her friends

• went

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12) identify the circled line in the sentence.

- All of the ((((PLAYERS)))) went to practice

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7 0
2 years ago
15.00 grams of Chromium react with 15.00 grams of hydrobromic acid. Calculate the theoretical yield of the reaction. At STP what
s2008m [1.1K]

Answer:

(a) 18.03 g

(b) 2.105 L

(c) 85.15 %

Step-by-step explanation:

We have the masses of two reactants, so this is a<em> limiting reactant problem.  </em>

We know that we will need a balanced equation with masses, moles, and molar masses of the compounds involved.  

<em>Step 1</em>. <em>Gather all the information</em> in one place with molar masses above the formulas and masses below them.  

M_r:        52.00   80.91       291.71

                2Cr  +  6HBr ⟶ 2CrBr₃ + 3H₂

Mass/g:  15.00    15.00  

<em>Step 2</em>. Calculate the <em>moles of each reactant</em>  

  Moles of Cr = 15.00 × 1/52.00

  Moles of Cr = 0.2885 mol Cr

Moles of HBr = 15.00 × 1/80.91

Moles of HBr = 0.1854 mol HBr ×  

<em>Step 3</em>. Identify the<em> limiting reactant</em>  

Calculate the moles of CrCl₃ we can obtain from each reactant.  

<em>From Cr</em>:

The molar ratio of CrBr₃:Cr is 2 mol CrBr₃:2 mol Cr

Moles of CrBr₃ = 0.2885 × 2/2

Moles of CrBr₃ = 0.2885 mol CrCl₃

<em>From HBr: </em>

The molar ratio of CrBr₃:HBr is 2 mol CrBr₃:6 mol HBr.

Moles of CrBr₃ = 0.1854 × 2/6

Moles of CrBr₃ = 0.061 80 mol CrBr₃

The limiting reactant is HBr because it gives the smaller amount of CrBr₃.

<em>Step 4</em>. Calculate the <em>theoretical yields</em> of CrBr₃ and H₂.

Theoretical yield of CrBr₃ = 0.061 80 × 291.71/1

Theoretical yield of CrBr₃ = 18.03 g CrCl₃

The molar ratio is 3 mol H₂:6 mol HBr

   Theoretical yield of H₂ = 0.1854 × 3/6

   Theoretical yield of H₂ = 0.092 70 mol H₂

<em>Step 5</em>. Calculate the <em>volume of H₂</em> at STP

STP is 1 bar and 0 °C.

The molar volume of a gas at STP is 22.71 L.

Volume = 0.092 70 × 22.71/1

Volume = 2.105 L

<em>Step 6</em>. Calculate the <em>percent yield </em>

       % Yield = actual yield/theoretical yield × 100 %

Actual yield = 15.35 g

       % yield = 15.35/18.03 × 100

       % yield = <em>85.15 % </em>

8 0
3 years ago
The chemical formula for the unknown molecule shown above is...
solmaris [256]

Answer:

dsrthsrhrhrhrthrsh

Explanation:

8 0
3 years ago
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