Answer:
c = 75
Hope this helps!
Step-by-step explanation:
c + 38 = 113
c + 38 - 38 = 113 - 38
c = 113 - 38
c = 75
Answer:

Step-by-step explanation:
In 2x/(x^2 - 1)1/2

Apply the property of natural log
ln x^m = m ln(x) move the exponent before ln


ln(m/n)= ln m - ln n

multiply 1/2 inside the terms

7/8 × 2 = 14/8
14 / 8 = 1.75
17.5 is the Answer
It's hard to explain by words so sorry if you don't understand. For the graphing part, starting from (-3, 0), plot points in (1, 2), (6, 3), and connect them. The end of a line should be (10, 3.5). You will understand better if you use graphing calculator.
The answer of a second question is {x|x is greater or equal to -3.
Answer:
a) 4 - 
b) 1 - 
c) 6 - 
Step-by-step explanation:
It simply asks the steps to go from the original displacement formula to isolate a (the acceleration). It's just a matter of moving items around.
We start with:

We then move the vt part on the left side, then multiply each side by -1 (to get rid of the negative on the at side and to match answer choice #4):

Then we multiply each side by 2 to get rid of the 1/2, answer #1:

Finally, we divide each side by t^2 to isolate a (answer #6):
