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Lostsunrise [7]
3 years ago
13

0.05555555555 as a simplified fraction. Please, I’m raging so much right now.

Mathematics
2 answers:
geniusboy [140]3 years ago
6 0

Answer:

\frac{1}{18}

Step-by-step explanation:

We require to create 2 equations with the repeating number placed after the decimal point.

let x = 0.055555 ( multiply both sides by 10 and 100 )

10x = 0.555555 → (1)

100x = 5.55555 → (2)

Subtract (1) from (2) to eliminate the repeating decimal

90x = 5 ( divide both sides by 90 )

x = \frac{5}{90} = \frac{1}{18}

Artemon [7]3 years ago
5 0

Answer:

5555555555/100000000000

Step-by-step explanation:

I guess I am not sure though.

Can you help me with my question?

PLS HELP ASAP!!!!

A restaurant wants to study how well it's salads sell. the circle graph shows the sales over the past few days. If 15 of the salads sold were caesar salads, how many total salads did the restaurant sell Caesar 30% Garden 58% Cobb 12%?

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8 because 2 times 5 is ten
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Question 8, thanks guys
Natasha2012 [34]

Answer:

B.

Step-by-step explanation:

Use the multiplication table of 12 and find that 5x12=60. Answer B is the only one that has that.

5 0
3 years ago
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At the Hula Factory, the assembly line produces 212 leis in a batch. The leis are packaged in boxes with 30 each. If 14 batches
nikklg [1K]

Answer:

197 leis left over

Step-by-step explanation:

14 times 212 = 2968

2968/30 = 98.93

212 times 0.93 = 197

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7 0
2 years ago
Please help with imaginary numbers worksheet!
mihalych1998 [28]

Problem 5

<h3>Answer:   6i</h3>

------------------

Explanation:

We have these four identities

  • i^0 = 1
  • i^1 = i
  • i^2 = -1
  • i^3 = -i

Notice how computing i^4 leads us back to 1. So i^4 = i^0. The pattern repeats every 4 terms. So we divide the exponent by 4 and look at the remainder. We ignore the quotient entirely. We can see that 28/4 = 7 remainder 0. Meaning that i^28 = i^0 = 1.

We can think of it like this if you wanted

i^28 = (i^4)^7 = 1^7 = 1

Then the sqrt(-36) becomes 6i

So overall, we end up with the final answer of 6i

=============================================

Problem 6

<h3>Answer:  -3i</h3>

------------------

Explanation:

We'll use the ideas mentioned in problem 5

46/4 = 11 remainder 2

i^46 = i^2 = -1

sqrt(-9) = 3i

The two outside negative signs cancel out, but there's still a negative from -1 we found earlier. So we end up with -3i

In other words, here is one way you could write out the steps

-i^{46}*-\sqrt{-9}\\\\-i^{2}*-3i\\\\i^{2}*3i\\\\-1*3i\\\\-3i\\\\

=============================================

Problem 7

<h3>Answer:   -1</h3>

------------------

Work Shown:

i^10 = i^2 because 10/4 = 2 remainder 2

i^19 = i^3 because 19/4 = 4 remainder 3

i^7 = i^3 because 7/4 = 1 remainder 3

Again, all we care about are the remainders.

i^{10}+i^{19} - i^{7}\\\\i^{2}+i^{3} - i^{3}\\\\i^{2}\\\\-1

=============================================

Problem 8

<h3>Answer:    -1 + i</h3>

------------------

Work Shown:

i^22*i^6 = i^(22+6) = i^28

Earlier in problem 5, we found that i^28 = i^0 = 1

So,

i^1 - \left(i^{22}*i^{6}\right)\\\\i^1 - i^{28}\\\\i^1 - i^{0}\\\\i - 1\\\\-1+i

8 0
2 years ago
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Please help evaluate?
Dominik [7]
3. 

4^3 is equal to 64. Therefor log4(64) must be equal to 3. 
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