the probability that if you pick only one, it's defective, is 250/6700
Therefore, the probability that one is not defective is 6450/6700
a. You want all 4 to not be defective: (6450/6700)^4
b. all 100 have to be not defective: (6450/6700)^100
If you type this into a calculator, you will get about 0.022, so a probability of 2 % that all of them are not defective. As this is a very small probability, the outlet should plan with returned tires.
So the function we're dealing with is
f(x) =
Factorising we get,
Therefore, the vertical asymptotes are at x = 3 and x = 6
Let
N--------> <span>members of the club
we know that
($192/(N+2)=3.20
192=(N+2)*3.20
3.20*N+6.40=192
3.20*N=192-6.40
N=185.60/3.20
N=58
the answer is
58</span>
Answer:
12x^18
Step-by-step explanation:
Answer:
-1/64
Step-by-step explanation:
Just do 4 to the 3rd and make that the denominator
4^3 = 64
-1 / 64
