There is 6 parts in a two column format.
When two parallel lines are intersected by a transversal, the same-side exterior angles are supplementary. That means that their sum is 180.
Using that logic, if the two roads were parallel, then the sum of their same-side exterior angles will add up to 180. Yet their same-side exterior angles add up to 170 (130 + 40 = 170), hence they can't be parallel.
See the drawing attached below.
Using supplmenatry angles (two angles whose sum of measures add up to 180 or a straight line), we can say that:
m<DIE + m<HID = 18
40 + m<HID = 180
m<HID = 140
Similarly:
m<BHC + m<CHI = 180
130 + m<CHI = 180
m<CHI = 50
Using verticle angles therome, (when two lines intersect, the angles opposite to eachother are congruent, or have the same measure), we can say that:
m<DIE = m<GIH = 40
m<GIE = m<HID = 140
m<CHI = m<AHB = 50
m<BHC = m<AHI = 130
Hello!
The problem has asked that we write a
point-slope
equation of the line in the image above.
Point-Slope Form uses the following formula:
y –

= m(x –

)
In this case, M represents the
slope while

and

represent the
corresponding X and Y values of any given point on the line.
We are given that the slope of the line is -

. We also know that any given point on a graph takes the form (x,y). Based on the single point provided in the image above, we can determine that

is equal to
6 and

is equal to
2. Now insert all known values into the point-slope formula above:
y – 2 = -

(x – 6)
We have now successfully created an equation based on the information given in the problem above. Looking at the four possible options, we can now come to the conclusion that
the answer is C.
I hope this helps!