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dybincka [34]
3 years ago
9

Find m<14 if m<13=115º.

Mathematics
1 answer:
salantis [7]3 years ago
8 0

Answer:

115

Step-by-step explanation:

Since line v and line u are parallel:

m<14 and m<13 must be alternate exterior angles and alternate exterior angles has equal measure so the answer is:

m<13 = m<14 = 115.

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Sam Is 11 years older than Susan the sum of their ages in years is 27 what’s sams age in years
sweet [91]

Answer:

19

Step-by-step explanation:

Let Sam be x

Let Susan be y


x = y+11

x + y = 27

Substitute (x) with (y+11)

(y+11) + y = 27

Solve the equation

2y + 11 = 27

2y = 16

y = 8


Susan's age is 8.

Sam's age is 8 + 11

Sam's age is 19


Hope this helped :)

5 0
3 years ago
Read 2 more answers
A 75-gallon tank is filled with brine (water nearly saturated with salt; used as a preservative) holding 11 pounds of salt in so
Debora [2.8K]

Let A(t) = amount of salt (in pounds) in the tank at time t (in minutes). Then A(0) = 11.

Salt flows in at a rate

\left(0.6\dfrac{\rm lb}{\rm gal}\right) \left(3\dfrac{\rm gal}{\rm min}\right) = \dfrac95 \dfrac{\rm lb}{\rm min}

and flows out at a rate

\left(\dfrac{A(t)\,\rm lb}{75\,\rm gal + \left(3\frac{\rm gal}{\rm min} - 3.25\frac{\rm gal}{\rm min}\right)t}\right) \left(3.25\dfrac{\rm gal}{\rm min}\right) = \dfrac{13A(t)}{300-t} \dfrac{\rm lb}{\rm min}

where 4 quarts = 1 gallon so 13 quarts = 3.25 gallon.

Then the net rate of salt flow is given by the differential equation

\dfrac{dA}{dt} = \dfrac95 - \dfrac{13A}{300-t}

which I'll solve with the integrating factor method.

\dfrac{dA}{dt} + \dfrac{13}{300-t} A = \dfrac95

-\dfrac1{(300-t)^{13}} \dfrac{dA}{dt} - \dfrac{13}{(300-t)^{14}} A = -\dfrac9{5(300-t)^{13}}

\dfrac d{dt} \left(-\dfrac1{(300-t)^{13}} A\right) = -\dfrac9{5(300-t)^{13}}

Integrate both sides. By the fundamental theorem of calculus,

\displaystyle -\dfrac1{(300-t)^{13}} A = -\dfrac1{(300-t)^{13}} A\bigg|_{t=0} - \frac95 \int_0^t \frac{du}{(300-u)^{13}}

\displaystyle -\dfrac1{(300-t)^{13}} A = -\dfrac{11}{300^{13}} - \frac95 \times \dfrac1{12} \left(\frac1{(300-t)^{12}} - \frac1{300^{12}}\right)

\displaystyle -\dfrac1{(300-t)^{13}} A = \dfrac{34}{300^{13}} - \frac3{20}\frac1{(300-t)^{12}}

\displaystyle A = \frac3{20} (300-t) - \dfrac{34}{300^{13}}(300-t)^{13}

\displaystyle A = 45 \left(1 - \frac t{300}\right) - 34 \left(1 - \frac t{300}\right)^{13}

After 1 hour = 60 minutes, the tank will contain

A(60) = 45 \left(1 - \dfrac {60}{300}\right) - 34 \left(1 - \dfrac {60}{300}\right)^{13} = 45\left(\dfrac45\right) - 34 \left(\dfrac45\right)^{13} \approx 34.131

pounds of salt.

7 0
2 years ago
375 ÷ 3 = n. what do you guys think it is answers?????
morpeh [17]

Answer:125=n

Step-by-step explanation: 375 divided by 3 is 125

7 0
1 year ago
Read 2 more answers
At Ralph's fruitstand three apples cost of $.90 you want to buy seven apples how much will they cost
Nata [24]
1 apple is $.30. $.30 times 7 = $2.10. 
3 0
3 years ago
What is length?define​
pogonyaev

Step-by-step explanation:

the measurement or extent of something from end to end; the greater of two or the greatest of three dimensions of an object.

7 0
3 years ago
Read 2 more answers
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