Given the relationship T^2 = A^3, to compare the values of the orbital periods of X and Y, it would be easier to assign values. Since the Planet Y's distance A is twice that of Planet X's distance A, this can be shown below:
For Planet X (where A = 2):
T^2 = 2^3
T = 2.828
For Planet Y (where A = 4)
T^2 = 4^3
T = 8
Therefore, planet Y's orbital period is larger by (8/2.828) = 2.83 times.
Answer:
$145.80
Step-by-step explanation:
The original cost of the product was $90. There was a 162% markup. In order to get the selling price, I like to take away 100 percent and simply add original price+(original price*62%). After taking away 100%, I am left with 62%. I then multiply the original cost ($90) by the remaining percent (62%), getting 55.8. Following the steps that I originally wrote, I now add 90 to 55.8, getting 145.8.
The mixed number for 128.34 is 128 17/50
The answer is 7.41717 x 10^4 because you move the decimal to the left 4 spaces
Answer:
Dividing two functions works in a similar way.
Step-by-step explanation: