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larisa [96]
3 years ago
5

A 40.0-kg football player leaps through the air to collide with and tackle a 50.0-kg player heading toward him, also in the air.

If the 40.0-kg player is heading to the right at 9.0 m/s and the 50.0-kg player is heading toward the left at 2.0 m/s, what is the speed and direction of the tangled players
Physics
1 answer:
lara31 [8.8K]3 years ago
5 0

Answer:

The speed and direction of the tangled players is 2.89 m/s towards right.

Explanation:

Given;

mass of the player heading right, m₁ = 40 kg

initial velocity of the player heading right, u₁ = 9.0 m/s

mass of the player heading left, m₂ = 50 kg

initial velocity of the player heading left, u₂ = -2.0 m/s

let the speed of the tangled players = v

Apply the law of conservation of linear momentum;

m₁u₁ + m₂u₂ = v(m₁ + m₂)

(40 x 9) + (50 x - 2) = v(40 + 50)

360 - 100 = v(90)

260 = v(90)

v = 260 / 90

v = 2.89 m/s (towards right, since it is in position direction)

Therefore, the speed and direction of the tangled players is 2.89 m/s towards right.

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tino4ka555 [31]

Answer:

(1) Offer the right benefits

(2) Be transparent and open

Explanation:

There are two key strategies for retaining step are discussed below:

(1) Offer the right benefits: Benefits and perks can play a very good role in keeping employees happy, healthy and engaged. But benefits can go far beyond paid sick leaves and health coverage.

The company can give some financial awards to the employees which can help in exceeding performance and by this employees will stay in the company for a long period. Nearly 9 out of 10 companies will provide incentives and bonuses to the employees in coming next five years, according to the CTA.

(2) Be transparent and open: Creating open communication between the management and employees will help in the growth of the company as well as make the office atmosphere good. By this employees can share the ideas with the management and by these meetings, the employees can share their problems with management frankly will help employees to stay in the company for a longer period.

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3 years ago
A man who works for a moving company is loading a box onto a moving van. He pushes a 200N box up a 5m long ramp. If he pushes wi
OlgaM077 [116]

Answer:

η = 0.667 = 66.7%

Explanation:

The efficiency of the man can be given by the following formula:

η = output/input

where,

η = efficiency of man = ?

output = potential energy gain of the box = Wh

input = work done by man = Fd

Therefore,

\eta = \frac{Wh}{Fd}

where,

W = weight of box = 200 N

h = height gained by box = 1 m

F = force exerted by man = 60 N

d = length of ramp = 5 m

Therefore,

\eta = \frac{(200\ N)(1\ m)}{(60\ N)(5\ m)}

<u>η = 0.667 = 66.7%</u>

8 0
3 years ago
What family of elements has 7 valence electrons?
ivann1987 [24]
Group 17 (VII) (halogens)
4 0
3 years ago
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The resistance of the body varies from approximately 500 kΩ (when it is very dry) to about 1.20 kΩ (when it is wet). The maximum
scoray [572]

Answer:

a) The maximum potential difference the wet human body can take = 5.88 V

b) This value is very much lower than the normal voltage of household outlets (120 V) and isn't in the same range at all.

This means one should be very careful operating electrical appliances (even at home) while the body is wet.

Explanation:

From Ohm's law, V = IR

The resistance of the body when the body is wet = 1.2 kΩ = 1200 Ω

Maximum safe current that the body can withstand = 4.90 mA = 0.0049 A

Maximum voltage the body can withstand while wet = (Maximum safe current that the body can withstand) × (Resistance of the body when the body is wet) = 0.0049 × 1200 = 5.88 V

b) This value is still very much lower than the normal voltage of household outlets (120 V) and isn't in the same range at all.

This means one should be very careful operating electrical appliances (even at home) while the body is wet.

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