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I am Lyosha [343]
3 years ago
7

Determine the gravitational force of attraction experienced by a two 5.00 kilogram masses separated by a distance of 2.5 meters.

Physics
1 answer:
drek231 [11]3 years ago
4 0
The gravitational force between two objects may be calculated through the equation,
                                     F = Gm₁m₂ / d²
where G is 6.67 x 10^-11 m³/s²kg
Substituting the known values to the equation,
                        F = (6.67 x 10^-11 m³/s²kg)(5.0 kg)(5.0 kg) / (2.5 m)²
                                     F = 2.668 x 10^-10 N
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as the trait is dominant and controlled by a single gene,the mutation must have occurred on both diploid copies. true or false?
GenaCL600 [577]

Answer:

False

Explanation:

A dominant trait is a trait that is inherited from parents. It is a trait that is obtained from a particular copy or type of a gene that overshadows or overwhelms the effects of another type or copy of that gene. Dominant traits are controlled by a single gene.

Therefore , as the trait is dominant and controlled by a single gene,the mutation must have occurred on both diploid copies is a false statement.

5 0
3 years ago
Now assume that the stream flows east at 4.0 m/s. draw the vectors v⃗ w, representing the velocity of the stream, and v⃗ tot, re
ELEN [110]

Remember that the total velocity of the motion is the vector sum of the velocity you would have in still water and the stream. Always place the vectors carefully to be able to come up with an accurate sum vector.

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3 0
3 years ago
This questic concerns a tablet that
Vanyuwa [196]

Answer:

The remaining percentage of drug concentration is about 88.7% 2 years after manufacture.

Explanation:

Recall the formula for the decay of a substance at an initial N_0 concentration at manufacture:

N(t)=N_0\,e^{-k\,\,t}

where k is the decay rate (in our case 0.06/year), and t is the elapsed time in years. Therefore, after 2 years since manufacture we have:

N=N_0\,e^{-0.06\,\,(2)}\\N=N_0\,e^{-0.12}\\N/N_0=e^{-0.12}\\N/N_0=0.8869

This in percent form is 88.7 %. That is, the remaining percentage of drug concentration is about 88.7% 2 years after manufacture.

3 0
3 years ago
What is the kinetic energy of a 1,350kg car traveling at a speed of 12m/s?
Ainat [17]
Kinetic energy= 1/2 m v^2

so... 1/2(1350)(12^2)

kinetic energy = 97200Joules
7 0
2 years ago
A uniform electric field of 2 kNC-1 is in the x-direction. A point charge of 3 μC initially at rest at the origin is released. W
ANEK [815]
The electric force acting on the charge is given by the charge multiplied by the electric field intensity:
F=qE
where in our problem q=3 \mu C= 3 \cdot 10^{-6} C and E=2 kN/C=2000 N/C, so the force is
F=(3 \cdot 10^{-6} C)(2000 N/C)=0.006 N

The initial kinetic energy of the particle is zero (because it is at rest), so its final kinetic energy corresponds to the work done by the electric force for a distance of x=4 m:
K(4 m)=W=Fd=(0.006 N)(4 m)=0.024 J
8 0
3 years ago
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