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olya-2409 [2.1K]
3 years ago
7

A thermometer that uses a liquid to measure temperature works because

Physics
2 answers:
pav-90 [236]3 years ago
6 0
The liquid in a thermometer is sometimes colored alcohol but can also be a metallic liquid called mercury. Mercury and alcohol expand when heated and shrink when cooled. Inside the glass tube of a thermometer, the liquid has no place to go but up when the temperature is hot and down when the temperature is cold. That's how a thermometer that uses liquid to measure temperature.
PSYCHO15rus [73]3 years ago
5 0
A rule of thumb is that liquid expands when heated, so when liquid is in a given space one can measure how far the liquid moves when it gets heated.
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Which of these would most likely cause a sound wave?
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Among the choices the one that most likely cause a sound wave is C or the a spoon hitting the side of a bowl while mixing <span>because that's going to make a sound.

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A cylinder contains a mixture of helium and argon gas in equilibrium at 160°C.
Artist 52 [7]

Answer:

a. E=8.97*10^{-21} J

b. v-He2 = 1.161 km/s

v-Ar2 = 369.74 m/s

Explanation:

(a) The average kinetic energy is given by

E_k=\frac{1}{2}k_BT

where KB is the Boltzman's constant and T is the temperature. For each molecule we have:

E_k=\frac{3}{2}(1.38066*10^{-23}\frac{J}{K})(433.15K)=8.97*10^{-21}J

is the same for both type of molecules because is independent of the mass

(b)

v_{rms}=\sqrt{\frac{3RT}{M}}

where R is the constant of ideal gases, and M is the mass of the molecule. BY replacing for each type of molecule we obtain:

v_{rms-He_{2}}=\sqrt{\frac{3(8.311434Jmol^{-1}K^{-1})(433.15K)}{0.008kg\ mol^{-1}}}=1161.9\frac{m}{s}\\\\v_{rms-Ar_{2}}=\sqrt{\frac{3(8.311434Jmol^{-1}K^{-1})(433.15K)}{0.079kg\ mol^{-1}}}=369.74\frac{m}{s}

v-He2 = 1.161 km/s

v-Ar2 = 369.74 m/s

hope this helps!!

8 0
3 years ago
In the form of radioactive decay known as alpha decay, an unstable nucleus emits a helium-atom nucleus, which is called an alpha
trapecia [35]

Answer:

Velocity will be v=4.06\times10^7m/sec

Explanation:

We have given mass of alpha particle m = 4 u =4\times 1.67\times 10^{-27}kg=6.68\times 10^{-27}kg

Charge on alpha particle q=2e=2\times 1.6\times 10^{-19}C=3.2\times 10^{-19}C

Charge on thorium particle =90\times 1.6\times 10^{-19}=144\times 10^{-19}C

Diameter is given as d = 15 fm

So radius r=\frac{d}{2}=\frac{15}{2}=7.5fm=7.5\times 10^{-15}m

Potential energy is given by E=\frac{1}{4\pi \epsilon _0}\frac{q_1q_2}{r}=\frac{Kq_1q_2}{r}=\frac{9\times 10^9\times 144\times 10^{-19}\times 3.2\times 10^{-19}}{7.5\times 10^{-15}}=5.529\times 10^{-12}J

From energy conservation \frac{1}{2}mv^2=5.529\times 10^{-12}

\frac{1}{2}\times 6.68\times 10^{-27}v^2=5.529\times 10^{-12}

v=4.06\times10^7m/sec

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