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3 years ago

Name the following FBr?

1 answer:

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Federal Board of Revenue
Not sure of this helped, if it was useful, please make me the brainliest!! Have a good day/night

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The temperature at which a substance in the liquid phase transforms to the gaseous phase refers to the substance's _______. A. s

murzikaleks [220]

When a substance goes from being a liquid to a gas it evaporates, or boils away. Think of boiled eggs.

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3 years ago

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Which product forms from a reaction between beryllium (Be) and arsenic (As)?

Gekata [30.6K]

Answer:

Be3As2

Explanation:

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3 years ago

I really need help with this I would really appreciate it

gulaghasi [49]

PV=nRT will give you the answer I think. I haven’t worked with a certain unit in that problem

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3 years ago

Part complete When a 235 92U nucleus is bombarded by neutrons (10n) it undergoes a fission reaction, resulting in the formation

nikdorinn [45]

Answer: The isotopic symbol of barium is $_{56}^{138}\textrm{Ba}$ and that of strontium is $_{38}^{89}\textrm{Sr}$

Explanation:

Nuclear fission reactions are defined as the reactions in which a heavier nuclei breaks down in two or more smaller nuclei.

In a nuclear reaction, the total mass and total atomic number remains the same.

For the given fission reaction:

$^{235}_{92}\textrm{U}+^1_0\textrm{n}\rightarrow ^A_Z\textrm{Ba}+^{94}_{36}\textrm{Kr}+3^1_0\textrm{n}$

To calculate A:

Total mass on reactant side = total mass on product side

235 + 1 = A + 94 + 3

A = 139

To calculate Z:

Total atomic number on reactant side = total atomic number on product side

92 + 0 = Z + 36 + 0

Z = 56

The isotopic symbol of barium is $_{56}^{139}\textrm{Ba}$

For the given fission reaction:

$^{235}_{92}\textrm{U}+^1_0\textrm{n}\rightarrow ^A_Z\textrm{Sr}+^{143}_{54}\textrm{Xe}+3^1_0\textrm{n}$

To calculate A:

Total mass on reactant side = total mass on product side

235 + 1 = A + 143 + 3

A = 90

To calculate Z:

Total atomic number on reactant side = total atomic number on product side

92 + 0 = Z + 54 + 0

Z = 38

The isotopic symbol of strontium is $_{38}^{89}\textrm{Sr}$

Hence, the isotopic symbol of barium is $_{56}^{138}\textrm{Ba}$ and that of strontium is $_{38}^{89}\textrm{Sr}$

7 0

3 years ago

Help idk how to do this

maksim [4K]

Answer:

Explanation:

so we have to solve it or just answer it?

8 0

3 years ago