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Maurinko [17]
3 years ago
15

Can someone help me with Q4 MCQ? I would like to have an explanation pls. Thanks, will mark brainliest.

Chemistry
1 answer:
lilavasa [31]3 years ago
8 0

Answer:

B

Explanation:

The ratios of the coefficient of the compounds in a balanced chemical equation tells us the relationship of each compound to the others in terms of mole.

Based on the equation,

3 moles of CO₂ would require 2 moles of phosphoric acid.

3 mol CO₂ ------- 2 mol H₃PO₄

1.5 mol CO₂ ------- 2 ÷2= 1 mol H₃PO₄

Or 1.5 mol would require \frac{1.5}{3}  \times 2 mol of  H₃PO₄

To find mass of  H₃PO₄, multiply the number of moles by its Mr, which can be deduced with the help of the periodic table.

Ar of  H₃PO₄

= 3(Ar of H) + Ar of P +4(Ar of O)

= 3(1) +31 +4(16)

= 98

Multiply 98 with the number of moles, 1, to obtain the answer.

So if you would look at the steps above, here's what we did:

\frac{1.5 \times 2}{3}  \times 98 \\  =  \frac{1.5 \times 2 \times 98}{3}

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A burning candle demonstrates the following type of energy transformations.
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Answer:

B

Explanation:

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2 years ago
4 Nitrogen monoxide reacts with oxygen like this:
olga2289 [7]

a. mol O₂=0.5

b. volume O₂ = 25 cm³

c. i. the total volume of the two reactants = 75 cm³

c. ii. the volume of nitrogen dioxide formed = 50 cm³

<h3>Further explanation</h3>

Reaction

2NO(gas) + O₂(gas) ⇒ 2NO₂ (gas)

a.

mol NO = 1

From the equation, mol ratio NO : O₂ = 2 : 1, so mol O₂ :

\tt \dfrac{1}{2}\times 1=0.5

b.

From Avogadro's hypothesis, at the same temperature and pressure, the ratio of gas volume will be equal to the ratio of gas moles  

Because mol ratio NO : O₂ = 2 : 1, so volume O₂ :

\tt \dfrac{1}{2}\times 50~cm^3=25~cm^3

c.

i. total volume of reactants : 25 cm³+ 50 cm³=75 cm³

ii. the volume of nitrogen dioxide formed :

mol ratio NO : NO₂ = 2 : 2, so volume NO₂ = volume NO = 50 cm³

6 0
2 years ago
I will go to the app and give you brainly Est if u answer correctly ASAPPPPP
zhuklara [117]

Answer:

C

Explanation:

I think it is C

4 0
2 years ago
A compound with the empirical formula CH 2 O has a formula mass of 180 g/mol. What is its molecular formula
olga nikolaevna [1]

Empirical formula mass

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  • 30g/mol

Molecular fornula mass:-180g/mol

  • n=Molecular formula mass/Empirical formula mass
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  • n=6

Molecular formula:-

  • n×Empirical formula
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0.820 L has a mass of 2.56kg what is the density of this liquid in kg/L
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Density ρ=\frac{m}{v}

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8 0
3 years ago
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