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olganol [36]
3 years ago
6

Atomic energy is produced from changes within the_____ of an atom.

Physics
2 answers:
Iteru [2.4K]3 years ago
6 0

Answer:

nucleus

Explanation:

crimeas [40]3 years ago
4 0

Answer:

Atomic energy is produced from changes within the <u>nucleus</u> of an atom.

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How to find the value of sin(90+ theta) ?
koban [17]
Sin(90 + θ)

By addition angle formula for sine.

sin90cosθ + cos90sinθ

1*cosθ + 0*sinθ

cosθ + 0

= cosθ

sin(90 + θ) = cosθ
6 0
3 years ago
Which of the following best describes the internal layering of Jupiter, from the center outward?A) Core of rock and metal; mantl
statuscvo [17]

Answer:

Option D

Explanation:

Jupiter is made almost totally from hydrogen and some hydrogen compounds. It may have a solid hydrogen core, then a liquid hydrogen layer, then a gaseous layer.  

It is not known if Jupiter has a solid surface, or even a liquid surface. We measure Jupiter's diameter from the top of its gas layer.

The core is often described as rocky, but its detailed composition is unknown, as are the properties of materials at the temperatures and pressures.

The presence of a core during at least part of Jupiter's history is suggested by models of planetary formation that require the formation of a rocky or icy core massive enough to collect its bulk of hydrogen and helium from the protosolar nebula. Assuming it did exist, it may have shrunk as convection currents of hot liquid metallic hydrogen mixed with the molten core and carried its contents to higher levels in the planetary interior. A core may now be entirely absent, as gravitational measurements are not yet precise enough to rule that possibility out entirely.

8 0
3 years ago
a crowbar having the lenght of 1.75 is used to balance a load of 500N if the distance between the fulcrum and the load is 0.5m f
Lemur [1.5K]

The effort applied = 200 N

<h3>Further explanation</h3>

Equilibrium :

\tt F_1.d_1=F_2.d_2

Total length = 1.75

The distance between the fulcrum and the load is 0.5 m ⇒ d₁=0.5 m

The distance between the fulcrum and the force applied :

\tt 1.75-0.5=1.25~m\rightarrow d_2=1.25~m

A load of 500N ⇒ F₁=500 N

The force applied :

\tt 500\times 0.5=F_2\times 1.25\\\\F_2=\dfrac{500\times 0.5}{1.25}=200~N

7 0
3 years ago
suppose you are in a car driving down a road. a large truck passes your car. what does the car have a tendency to do?
balandron [24]

it moves toward the truck because increased air movement between the car and the truck decreases pressure.

Hope this helped :) <3

6 0
3 years ago
Read 2 more answers
A stone is dropped from the upper observation deck of a tower, 750 m above the ground. (assume g = 9.8 m/s2.) (a) find the dista
Gekata [30.6K]
(a) The stone moves by uniform accelerated motion, with constant acceleration g=9.81 m/s^2 directed downwards, and its initial vertical position at time t=0 is 750 m. So, the vertical position (in meters) at any time t can be written as
y(t)= y_0 -  \frac{1}{2}gt^2= 750 - 4.9 t^2

(b) The time the stone takes to reach the ground is the time at which the vertical position of the stone becomes zero: y(t)=0. So, we can write
750-4.9 t^2 = 0
from which we find the time t after which the stone reaches the ground:
t= \sqrt{\frac{750 m}{4.9 m/s^2 }}= 12.37 s

(c) The velocity of the stone at time t can be written as
v(t) = -gt
because it is an accelerated motion with initial speed zero. Substituting t=12.37 s, we find the final velocity of the stone:
v(12.37 s)=-(9.81 m/s^2)(12.37 s)=-121.3 m/s

(d) if the stone has an initial velocity of v_0 = 6 m/s, then its law of motion would be
y(t)=y_0 - v_0t -  \frac{1}{2}gt^2
and we can find the time it needs to reach the ground by requiring again y(t)=0:
0=750 - 6t - 4.9 t^2
which has two solutions: one is negative so we neglect it, while the second one is t=11.78 s, so this is the time after which the stone reaches the ground.

5 0
3 years ago
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