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Lapatulllka [165]

3 years ago

5

The higher heat capacity of water compared to rock or sediment means that for the same seasonal variation in insolation the land

temperature will vary ___________ the ocean.

1 answer:

Igoryamba3 years ago

5 0

"more than" is your answer

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Where is a water or a mechanical wave in which the particles in the medium move in a direction perpendicular to the direction of

horrorfan [7]

transverse waves. ripples on water surface

6 0

4 years ago

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Temperature which is solid becomes a liquid

Brums [2.3K]

Answer:

The answer would be melting point.

Explanation:

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5 0

3 years ago

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Which statement best defines constructive interference? O Energy reflects back toward the source of its power. O Two waves with

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Answer: two waves with identical crests and troughs meet

Explanation:

My teacher gave me the answer

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3 years ago

Special relativity can be used to study an object in which frame of reference?

Tresset [83]

Special relativity led the path for general relativity; special relativity is in a sense a special application of the rules of general relativity. While general relativity is in position to tackle all of these problems, special relativity can tackle only problems in inertial frames. Inertial frame means that the frame of reference is inot accelerating. So, we disqualify answers A and D. However, remember that moving in a circle means that there is an acceleration, the centrifugal one, even if the speed does not change. Hence C is also incorrect.
The correct answer is B, since if there is no change in velocity, the frame does not accelerate and it is inertial.

3 0

3 years ago

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A rock climber hangs freely from a nylon rope that is 15 m long and has a diameter of 8.3 mm. If the rope stretches 5.1 cm, what

irinina [24]

Answer:

Mass of the climber = 69.38 kg

Explanation:

Change in length

$\Delta L=\frac{PL}{AE}$

Load, P = m x 9.81 = 9.81m

Young's modulus, Y = 0.37 x 10¹⁰ N/m²

Area

$A=\frac{\pi (8.3\times 10^{-3})^2}{4}=5.41\times 10^{-5}m^2$

Length, L = 15 m

ΔL = 5.1 cm = 0.051 m

Substituting

$0.051=\frac{9.81m\times 15}{5.41\times 10^{-5}\times 0.37\times 10^{10}}\\\\m=69.38kg$

Mass of the climber = 69.38 kg

6 0

3 years ago