A boy rubs two balloons against his sweater. One balloon acquires a charge of 3.0 E -6 C. The other balloon acquires a charge of
1 answer:
Answer:
F= 67.5 N
Explanation:
We use the equation for the Coulomb's Law of Force between two charges Q1 and Q2 (in Coulombs) separated by a distance d (in meters):
where the constant k is the Coulomb's constant (
The charges are , Q2=2.5*10^{-7}C; the distance we convert into meters to match the appropriate units of the Coulomb constant k (1 cm = 0.01 m)
Now we input all these data into the equation, knowing that given the appropriate units, the force will be expressed in Newtons (N):
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Answer:
Refer to the attachment for the diagram.
3.53 m/s.
Explanation:
Acceleration is the first derivative of velocity relative to time. In other words, the acceleration is the same as the slope (gradient) of the velocity-time graph. Let represents the time in seconds and
the speed in meters-per-second.
For :
- Initial value of
:
at
; Hence the point on the segment:
.
- Slope of the velocity-time graph is the same as acceleration during that period of time:
.
- Find the equation of this segment in slope-point form:
.
Similarly, for :
- Initial value of
:
; Hence the point on the segment:
.
- Slope of the velocity-time graph is the same as acceleration during that period of time:
.
- Find the equation of this segment in slope-point form:
.
For :
- Initial value of
:
; Hence the point on the segment:
.
- Slope of the velocity-time graph is the same as acceleration during that period of time:
. There's no acceleration. In other words, the velocity is constant.
- Find the equation of this segment in slope-point form:
.
For :
- Initial value of
:
; Hence the point on the segment:
.
- Slope of the velocity-time graph is the same as acceleration during that period of time:
. In other words, the velocity is decreasing.
- Find the equation of this segment in slope-point form:
.
For :
- Initial value of
:
; Hence the point on the segment:
.
- Slope of the velocity-time graph is the same as acceleration during that period of time:
- Find the equation of this segment in slope-point form:
.
is in the interval
. Apply the equation for that interval:
.
Answer:
Explanation:
For parallel inductors ,
For series combination
Total inductance
= 16.67 + 20
= 36.67 mH .
reactance of total inductance at 300 kHz
= ω where ω is angular frequency
= 2πf
= 2 x 3.14 x 300 x 10³ x 36.67 x 10⁻³
= 69.1 x 10³ ohm
Total rms current = Vrms / reactance
= 60 / 69.1 x 10³ A
= .87 x 10⁻³ A
= .87 mA