1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Semmy [17]
3 years ago
6

The resistivity of a silver wire with a radius of 5.04 × 10–4 m is 1.59 × 10–8 ω · m. if the length of the wire is 3.00 m, what

is the resistance of the wire?
Physics
1 answer:
Alexxx [7]3 years ago
4 0
<span>5.98 x 10^-2 ohms. Resistance is defined as: R = rl/A where R = resistance in ohms r = resistivity (given as 1.59x10^-8) l = length of wire. A = Cross sectional area of wire. So plugging into the formula, the known values, including the area of a circle being pi*r^2, gives: R = 1.59x10^-8 * 3.00 / (pi * (5.04 x 10^-4)^2) R = (4.77 x 10^-8) / (pi * 2.54016 x 10 ^-7) R = (4.77 x 10^-8) / (7.98015 x 10^-7) R = 5.98 x 10^-2 ohms So that wire has a resistance of 5.98 x 10^-2 ohms.</span>
You might be interested in
suppose a ball is thrown vertically upward. Eight seconds later it returns to its point of release. What is the initial velocity
valentinak56 [21]
The ball took half of the total time ... 4 seconds ... to reach its highest
point, where it began to fall back down to the point of release.

At its highest point, its velocity changed from upward to downward. 
At that instant, its velocity was zero.

The acceleration of gravity is 9.8 m/s².  That means that an object that's
acted on only by gravity gains 9.8 m/s of downward speed every second. 

-- If the object is falling downward, it moves 9.8 m/s faster every second.

-- If the object is tossed upward, it moves 9.8 m/s slower every second.

The ball took 4 seconds to lose all of its upward speed.  So it must have
been thrown upward at  (4 x 9.8 m/s)  =  39.2 m/s .

(That's about  87.7 mph straight up.  Somebody had an amazing pitching arm.)
6 0
2 years ago
Help me on this question
nikitadnepr [17]
Adjust the height of the wooden rod so that it just touches the surface of the water. Switch on the lamp and motor and adjust the speed of the motor until low frequency waves can be clearly observed... Count the number of waves passing a point in ten seconds then Divide by ten to record frequency.
6 0
2 years ago
True or False!?
grin007 [14]
Solution= The answer is true

8 0
2 years ago
If the ball hits olaf and bounces off his chest horizontally at 8.50 m/s in the opposite direction, what is his speed vf after t
Feliz [49]

Answer:

16s/m

Explanation:

3 0
3 years ago
A change in the gravitational force acting on an object will affect the object
MArishka [77]
It is weight, if I understand your question.
4 0
3 years ago
Other questions:
  • A 0.21 kg baseball moving at +25 m/s is slowed to a stop by a catcher who exerts a constant force of −360 N. a) How long does it
    7·1 answer
  • Use an energy method to derive the equation of motion of the system in Problem 1.112. First with the presence of the damper and
    5·1 answer
  • A 12-kg lead brick falls from a height of 1.9 m. (c) The brick falls onto a carpet, 2.0 cm thick. Assuming the force stopping it
    10·1 answer
  • What happens to volume if pressure and temperature are doubled?
    6·1 answer
  • A cat has a mass of 3 kg and runs at a speed of 6 m/s. How much kinetic
    13·2 answers
  • a passenger on cruise between San Juan, Puerto Rico and Miami, Florida accidentally drops a souvenir metal cube over the side of
    15·1 answer
  • 1.Which car has zero acceleration?<br><br>2. which car is decelerating? ​
    14·1 answer
  • A bullet is fired from a rifle that is held 4.20 m above the ground in a horizontal position. The initial speed of the bullet is
    5·1 answer
  • Three cars (car F, car G, and car H) are moving with the same velocity, and slam on the brakes. The most massive car is car F, a
    7·1 answer
  • Please help!! Physics homework
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!