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Semmy [17]
3 years ago
6

The resistivity of a silver wire with a radius of 5.04 × 10–4 m is 1.59 × 10–8 ω · m. if the length of the wire is 3.00 m, what

is the resistance of the wire?
Physics
1 answer:
Alexxx [7]3 years ago
4 0
<span>5.98 x 10^-2 ohms. Resistance is defined as: R = rl/A where R = resistance in ohms r = resistivity (given as 1.59x10^-8) l = length of wire. A = Cross sectional area of wire. So plugging into the formula, the known values, including the area of a circle being pi*r^2, gives: R = 1.59x10^-8 * 3.00 / (pi * (5.04 x 10^-4)^2) R = (4.77 x 10^-8) / (pi * 2.54016 x 10 ^-7) R = (4.77 x 10^-8) / (7.98015 x 10^-7) R = 5.98 x 10^-2 ohms So that wire has a resistance of 5.98 x 10^-2 ohms.</span>
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The actual answer is 165 miles, but using significant figure rules the answer is 200. This is because the sig fig rules are as follows ...
<span>1. Non-zero digits are always significant.
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So the zeroes in a number like 20 or 23,000 are NOT significant. When you add numbers you must find the addend with the lowest amount of significant figures and round the answer to that. In this case most of the addends only have one sig fig, so you round 165 to 200 to make it only have one sig fig.
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2 years ago
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3 years ago
A partition divides an insulated tank into two parts. One part of the tank contains 2.5 kg of compressed liquid water at 60°C an
jeka94

Answer:

V=0.972m^2

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0=ΔU=mm(u_{2} -u_1)

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we replace the values in this equation:

x_2=\frac{251.6-191.79}{2245.4}\\ x_2=0.026

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we replace the values in this equation:

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V=mv_2

we replace the values in this equation:

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Answer:

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