The resistivity of a silver wire with a radius of 5.04 × 10–4 m is 1.59 × 10–8 ω · m. if the length of the wire is 3.00 m, what
1 answer:
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Answer:
4.63 p.m.
Explanation:
The problem given here can be solved by the Compton effect which is expressed as
here, is the initial photon wavelength,
is the scattered photon wavelength, h is he Planck's constant,
is the free electron mass, c is the velocity of light,
is the angle of scattering.
Given that, the scattering angle is,
Putting the respective values, we get
Therfore,
Here, the photon's incident wavelength is
So,
From the conservation of momentum,
here, is the initial photon momentum,
is the final photon momentum and
is the scattered electron momentum.
Expanding the vector sum, we get
Now expressing the momentum in terms of De-Broglie wavelength
and putting it in the above equation we get,
Therfore,
This is the de Broglie wavelength of the electron after scattering.
Answer:
4.9 m/s²
Explanation:
Draw a free body diagram. There are two forces on the object:
Weight force mg pulling straight down,
and normal force N pushing perpendicular to the plane.
Sum the forces in the parallel direction.
∑F = ma
mg sin θ = ma
a = g sin θ
a = (9.8 m/s²) (sin 30°)
a = 4.9 m/s²
