The output would depend on the input so relating this to the question, the input is the time (in minute) and the output is the amount of water left in the tank
We can give a letter 't' for the time, the input, and f(t) for the output
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The original amount of water in the tank is 10450, so this will be the fixed constant.
The amount of water lost per minute is 270 so this will be the term that varies depends on the variable of time, we write this as 270t
The function is given f(t) = 10450 - 270t
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Given, t = 10
f(10) = 10450 - 270(10)
f(10) = 7750 ml
Get rid of all common factors.
36/4 = 9
x^9/x^7 = x^2
y^4/y^3 = y
