Answer:
9 seconds
Step-by-step explanation:
The complete question is
The altitude of an object, d, can be modeled using the equation below:
d=-16t^2 +vt+h
from the edge of a 486 foot cliff, Peyton shot an arrow over the ocean with an initial upward velocity of 90 feet per second. In how many seconds will the arrow reach the water below?
Let
d ----> the altitude of an object in feet
t ---> the time in seconds
v ---> initial velocity in ft per second
h ---> initial height of an object in feet
we have

we know that
When the arrow reach the water the value of d is equal to zero
we have



substitute the values and solve for t


Multiply by -1 both sides

The formula to solve a quadratic equation of the form
is equal to
in this problem we have
substitute in the formula
the solution is t=9 sec
see the attached figure to better understand the problem
Two corresponding sides and two corresponding angles are congruent.
Quart because it's bigger than a pint and a quart is the closest to a gallon
Answer:
43.25
Step-by-step explanation:
Since sides DF and FE are congruent, their opposite angles D and E are also congruent.
m<D + m<E + m<F = 180
x + x + 93.5 = 180
2x = 86.5
x = 43.25
Answer: 43.25
39 it's an arithmetic sequence in which the common difference is +7