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3 years ago

What is the domain of the function f(x) = 2x /(3x^2− 3

Mathematics

2 answers:

bonufazy [111]3 years ago

7 0

Answer:

What is the range of the function? "All real numbers"

Step-by-step explanation:

Svet_ta [14]3 years ago

3 0

The domain of the function in this case will be for when the denominator is different from zero:
3x ^ 2- 3 = 0
3x ^ 2 = 3
x ^ 2 = 3/3
x ^ 2 = 1
x = + / - 1
Therefore the domain of this function are all reals without including x = 1 and x = -1

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Answer:

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3 years ago

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4/9 is in lowest terms.<br><br> A. True<br> B. False

vodomira [7]

Step-by-step explanation:

4/9 is in lowest terms because it does not have any other common factor , other than 1 so it can't be reduced more .

A. True

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With one method of a procedure called acceptance sampling, a sample of items is randomly selected without replacement and the en

GuDViN [60]

Answer:

$P = 0.1447$

Step-by-step explanation:

Given

$n = 7000$ -- total

$d = 180$ --- defective

$r = 6$ --- selected

Required

The probability of rejecting the batch

This means that at least one of the selected piece is defected.

So, we first calculate the probability that all the selected piece are accepted.

So, we have:

$Pr = \frac{7000 - 180}{7000} * \frac{6999 - 180}{6999}* \frac{6998 - 180}{6998}* \frac{6997 - 180}{6997}* \frac{6996 - 180}{6996}* \frac{6995 - 180}{6995}$

The denominator decreases by 1 because it is a probability without replacement; 180 is subtracted from the numerator to represent the number of non-defective CDs

So, we have:

$Pr = \frac{6820}{7000} * \frac{6819}{6999}* \frac{6818}{6998}* \frac{6817}{6997}* \frac{6816}{6996}* \frac{6815}{6995}$

$Pr = 0.8553$

Using the complement rule, the probability that the batch will be rejected is:

$P = 1 - 0.8553$

$P = 0.1447$

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