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Pavlova-9 [17]
2 years ago
9

The midpoint of line XZ is (2,-5). One endpoint is X(12,-5). Find the coordinates of the other endpoint Z

Mathematics
1 answer:
Inga [223]2 years ago
6 0

Answer: (-8,-5)

Step-by-step explanation:

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taurus [48]

Answer:

1399205

Step-by-step explanation:

6 0
3 years ago
Refer to the figure below to complete the following problem.
IRINA_888 [86]

Answer:

38

Step-by-step explanation:

5x-7=3x+ll

5x=3x+18

2x/2=18/2

x    =9

5 x 9 -7 = 36

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3 0
2 years ago
Can someone please help me with my maths question​
DIA [1.3K]

Answer:

a. \  \dfrac{625 \cdot m}{27 \cdot n^{11}}

b. \  \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}

Step-by-step explanation:

The question relates with rules of indices

(a) The give expression is presented as follows;

\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}

By expanding the expression, we get;

\dfrac{m^3 \times n^{-8} \times 5^4 \times m^4}{\left 3^3 \times m^6 \times n^3}

Collecting like terms gives;

\dfrac{m^{(3 + 4 - 6)}  \times 5^4}{ 3^3 \times n^{3 + 8}} = \dfrac{625 \cdot m}{27 \cdot n^{11}}

\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}= \dfrac{625 \cdot m}{27 \cdot n^{11}}

(b) The given expression is presented as follows;

x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \div (x \cdot y^n)^4

Therefore, we get;

x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times  x^{-4} \times y^{-4 \cdot n}

Collecting like terms gives;

x^{3 \cdot m + 2 - 4} \times \left (y^{3 \cdot n - 3 -4 \cdot n}} \right ) = x^{3 \cdot m - 2} \times \left (y^{ - 3 -n}} \right ) = x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right )

x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right ) = \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}

x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times  x^{-4} \times y^{-4 \cdot n} =\dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}

4 0
3 years ago
Which of the following equations represents a parabola that reaches its minimum value at (- 2, - 3)?
nlexa [21]
Yay me following equations
7 0
2 years ago
Find the product (4x-3) (3x+8)
m_a_m_a [10]

Hi there!

Assuming "Find the product" means multiplying (4x-3) by (3x+8) and factor to it's simplest form the answer would be:

12x²+23x-24

The way you solve this is by using the distributive property of multiplication as shown below:

Start by multiplying -3 from (4x-3) by everything in (3x+8)

3x*(-3) = -9x

8*(-3) = -24

Once you've done that you then multiply everything 4x

4x*8 = 32x

4x*3x = 12x²

(Note: when multiplying two of the same variables like x it means you are multiplying x by itself which is the same as x²)

When you put all of this together it looks like this

12x²+32x-9x-24

from there we combine like terms

32x-9x = 23x

to get

12x²+23x-24

I hope this helps!

God bless,

ASIAX

4 0
2 years ago
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