Answer:
null
Explanation:
it does not turn to null value. It returns ;
when it reaches the end of the file
Answer:
The Basic Program is as follows:
10 LENGTH = 50
15 WIDTH = 30
20 AREA = WIDTH * LENGTH
25 PRINT AREA
30 END
The Algorithm is as follows:
1. Start
2. Let Length = 50
3. Let Width = 30
4. Compute Area = Length * Width
5. Display Area
6. Stop
See Attachment for flowchart (flowchart is designed using draw io tools)
Explanation:
The flowchart, algorithm and basic program all follow the same sequence and explanation
Using the basic program as a case study;
Line number 10: The program starts by initializing LENGTH to 50
Line number 15: It then initializes WIDTH to 30
Line number 20: The AREA is calculated by LENGTH * WIDTH
Line number 25: The value of AREA is printed afterwards
Line number 30: Lastly, the program stops execution
Hello <span>Lcedillo7073 </span>
Answer: The world wide web was originally conceived of as a(n) Internal document management system
Hope this helps
-Chris
Well we have SRAM(Static Random Access Memory) is faster, have a lower density but it is more expensive.
While DRAM(Dynamic Random access memory) is just the opposite.
Those are the only two, I know exist.
Alternative 1:A small D-cache with a hit rate of 94% and a hit access time of 1 cycle (assume that no additional cycles on top of the baseline CPI are added to the execution on a cache hit in this case).Alternative 2: A larger D-cache with a hit rate of 98% and the hit access time of 2 cycles (assume that every memory instruction that hits into the cache adds one additional cycle on top of the baseline CPI). a)[10%] Estimate the CPI metric for both of these designs and determine which of these two designsprovides better performance. Explain your answers!CPI = # Cycles / # InsnLet X = # InsnCPI = # Cycles / XAlternative 1:# Cycles = 0.50*X*2 + 0.50*X(0.94*2 + 0.06*150)CPI= 0.50*X*2 + 0.50*X(0.94*2 + 0.06*150) / X1= X(0.50*2 + 0.50(0.94*2 + 0.06*150) ) / X= 0.50*2 + 0.50(0.94*2 + 0.06*150)= 6.44Alternative 2:# Cycles = 0.50*X*2 + 0.50*X(0.98*(2+1) + 0.02*150)CPI= 0.50*X*2 + 0.50*X(0.98*(2+1) + 0.02*150) / X2= X(0.50*2 + 0.50(0.98*(2+1) + 0.02*150)) / X= 0.50*2 + 0.50(0.98*(2+1) + 0.02*150)= 3.97Alternative 2 has a lower CPI, therefore Alternative 2 provides better performance.
