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Eddi Din [679]
3 years ago
7

Are the expressions x + x + 1 + x + 2 + x + 1 + x and 5x + 4 equivalent? Why or why not?

Mathematics
1 answer:
egoroff_w [7]3 years ago
3 0

Answer:

yes

they are equivalent because lets say the X = 3 then you would have to answer

3 + 3 + 1 + 3 + 2 + 3 + 1 + 3

and that would = 19

and then on the other equation

5 x 3 + 4 = 19

So the both equal the same.

PLZ MARK ME BRAINLIEST

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I’m so confused! Can someone help me with this? Please and thank you!
ludmilkaskok [199]

Answer:

D.

Step-by-step explanation:

1) the domain is x∈[0;+∞);

2) the solution is:

\sqrt{x}\leq 10; \ => \ x\leq 100;

3) finally, the solution with the domain is:

x∈[0;100].

7 0
2 years ago
ANSWER ALL THREE I WILL MAKE YOU THE BRAINLIEST EASY QUESTION
Anna35 [415]
Number 1 is 14/10 number 4 is 3 1/7 number 5 is 3 5/6
4 0
3 years ago
Read 2 more answers
Answering these questions
Rudiy27
1.\\ a)\ y=2x-3\ \ \ |subtract\ y\ from\ both\ sides\\\\\boxed{2x-y-3=0}\\\\b)\ y=\dfrac{1}{3}x-\dfrac{2}{5}\ \ \ |multiply\ both\ sides\ by\ 15\\\\15y=5x-3\cdot2\ \ \ |subtract\ 15y\ from\ both\ sides\\\\\boxed{5x-15y-6=0}


2.\\a)\ 5x-y+3=0\ \ \ |add\ y\ to\ both\ sides\\\\\boxed{y=5x+3}\\\\d)\ 7x+2y-3=0\ \ \ |subtract\ 7x\ from\ both\ sides\\\\2y-3=-7x\ \ \ |add\ 3\ to\ both\ sides\\\\2y=-7x+3\ \ \ \ |divide\ both\ sides\ by\ 2\\\\\boxed{y=-3.5x+1.5}


3.\\y=25x+100\ \ \ \ |subtract\ y\ from\ both\ sides\\\\\boxed{25x-y+100=0}
6 0
3 years ago
Rewrite as a simplified fraction.
Alex17521 [72]
1157/500 is as simple it can be as a fraction .
3 0
3 years ago
A machine shop produces heavy duty high endurance 20-inch rods that are meant for use in a variety of military grade equipment.
QveST [7]

Answer:

The probability that a defective rod can be salvaged = 0.50

Step-by-step explanation:

Given that:

A machine shop produces heavy duty high endurance 20-inch rods

On occasion, the machine malfunctions and produces a groove or a chisel cut mark somewhere on the rod.

If such defective rods can be cut so that there is at least 15 consecutive inches without a groove.

Then; The defective rod can be salvaged if the groove lies on the rod between 0 and 5 inches i.e ( 20  - 15 )inches

Now:

P(X ≤ 5) = \dfrac{5}{20}

= 0.25

P(X ≥ 15) = \dfrac{5}{20}

= 0.25

The probability that a defective rod can be salvaged = P(X ≤ 5) + P(X ≥ 15)

= 0.25+0.25

 = 0.50

∴ The probability that a defective rod can be salvaged = 0.50

4 0
3 years ago
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