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Vlada [557]
3 years ago
9

F(x) = x^3-15x^2+41x-15

Mathematics
1 answer:
blagie [28]3 years ago
8 0
X1= 6-square root of 31
X2= 3
X3= 6+square root of 31
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Plzzzz answer fast......​
Over [174]

Answer: (d)

Step-by-step explanation:

Given

XYZA is a rhombus and side XY is 8 units

We know, In a rhombus

  • All sides are equals
  • Diagonals bisect each other perpendicularly

Using the above property, we can write

XY=ZA=8\ \text{units}

Thus, option (d) is correct.

3 0
3 years ago
A case of 3 items costs $4.11 at Costco. what is the price of each item?
viva [34]
The price of each item is $1.37.
5 0
3 years ago
Read 2 more answers
Help me please !!!!!
MAVERICK [17]

The distance between these two animals is

3850

5 0
3 years ago
The heights in inches of males in the united states are believed to be approximately normally distributed with mean u the mean h
vovikov84 [41]

Answer:

Standard error = 0.83

Step-by-step explanation:

Given that the heights in inches of males in the united states are believed to be approximately normally distributed with mean u

Sample mean for 25 adults randomly taken =

\bar x = 69.72 inches

Std deviation of sample s = 4.15 inches

Since X  the height of males is Normal we find that the sample mean also will follow a normal distribution.

By central limit theorem, mean of x would be= sample mean= 69.72

Std error = \frac{s}{\sqrt{n} } =\frac{4.15}{5} \\=0.83

Standard error of the mean = std dev/square root of sample size.

Here only sample std deviation is known

So we used it

Standard error = 0.83

6 0
3 years ago
A rectangle has a width that is 5 feet less than the length. The area of the rectangle is 126 square feet. Find the dimensions o
mr_godi [17]

Given:

  • A rectangle has a width that is 5 feet less than the length. The area of the rectangle is 126 square feet

\\

❍Let's assume, Length of rectangle x feet and width of the rectangle x - 5 feet respectively.

\\

To calculate the dimensions of the rectangle we will use the formula of Area of rectangle:

\\

\:  \:  \:  \:  \:  \:  \: { \underline{ \boxed{ \pmb{ \frak{ Area_{(rectangle)}  = Length \times width }}}}} \\  \\

\\

\underline {\sf{Substituting  \: the \: values~ in~ above~formula: }} \\

\\

:  \implies \sf \:x \times (x - 5) = 126  \\  \\ \\ :  \implies \sf \:x^2 - 5x = 126  \\  \\ \\  :  \implies \sf \:x^2 - 5x - 126 = 0 \\  \\ \\ :  \implies \sf \:x^2 - 14x - 9x - 126 = 0 \\  \\ \\ :  \implies \sf \:x (x - 14) - 9 (x + 14) = 0 \\  \\ \\  :  \implies \sf \:(x - 14)(x - 9) = 0 \\  \\ \\  :  \implies { \boxed { \purple{\pmb { \: x = 14 \:   \: or  \: \:  x = -9}}} } \\  \\  \\

  • We know that side can't be negative. So, x = 14 feet

Hence,

  • Width of rectangle = x - 5 = 9 feet
  • Length of rectangle = x = 14 feet

\\

\\ { \underline{ \pmb{ \frak{\therefore Dimensions \:  of  \: rectangle  \: are  \: 9~ feet \:  and  \: 14 ~feet \: }}}}

3 0
3 years ago
Read 2 more answers
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