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navik [9.2K]
3 years ago
6

Students in physics lab times 10 oscillations of the pendulum and get 11.50 seconds how long is a pendulum in centimeters?

Physics
1 answer:
allochka39001 [22]3 years ago
7 0

Answer: 36.5

Explanation:

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A Boy can raise a load of 200N up to a<br>height of 2.5m in 15 seconds. calculate his<br>power​
shtirl [24]

Explanation:

f=mg

=200×10

=200N

Now,

work done=df

25×200

=500J

7 0
3 years ago
What is the distance that a car travels if it was brought to stop in 5 seconds and if it was traveling at 110 Km/h
Triss [41]

Answer:

Suppose that the acceleration is a constant, a.

a(t) = a.

To write the velocity equation, we must integrate over time, and the constant of integration will be equal to the initial velocity, in this case is 110km/h.

v(t) = a*t + 110km/h

And we know that at t = 5s, the car was brought to stop, so the velocity must be zero.

v(5s) = 0 = a*5s + 110km/h.

a = (110km/h)*(1/5s)

now we have that:

1 hour = 3600 seconds.

1km = 1000m

then:

110km/h = (110*1000/3600)m/s = 30.56 m/s

Then we have:

a = (-30.55 m/s)/5s = -6.11 m/s^2

Now the velocity equation is:

v(t) = -6.11m/s^2*t + 30.56m/s

To write the positon equation we must integrate over time again, we can get:

p(t) = (1/2)*(-6.11m/s^2)*t^2 + (30.56m/s)*t + p0

Where p0 is the initial position, here i will assume that is zero, because it does no really mater.

The total displacement of the car will be equal to p(5s)

p(5s) = (1/2)*(-6.11m/s^2)*(5s)^2 + (30.56m/s)*(5s) = 76.425 meters.

6 0
3 years ago
If the soccer ball has a mass of 284g, and gravitational force is 9.81 m/s2 on Earth, what is the weight of the soccer ball?
bagirrra123 [75]

Answer:

  1. <u>2.79 N</u>
  2. <u>8.34 N</u>
  3. <u>Watermelon</u>

Explanation:

<u>Weight of soccer ball</u>

  • Weight = mass (in kg) × gravitational force
  • Weight = 284 x 10⁻³ x 9.81
  • Weight = 0.284 x 9.81
  • Weight = <u>2.79 N</u> (approximately)

<u>Weight of watermelon</u>

  • Weight = mass (in kg) x gravitational force
  • Weight = 850 x 10⁻³ x 9.81
  • Weight = 0.85 x 9.81
  • Weight = <u>8.34 N</u> (approximately)

As the <u>watermelon</u> has more weight, it will hit the ground first.

4 0
2 years ago
The Bohr model below represents which answer Choice
Anton [14]

Answer:

Na⁺

Explanation:

In the given atom:

  Number of protons  = 11

  Number of neutrons  = 12

So, the number of electrons  = 10

The number of protons within an atom is used to determine the kind of atom we have been given.

Since the number of protons is the same as the atomic number, here the atomic number is 11 and this is Sodium .

 In this sodium atom, the number of protons is more than the number of electrons;

 Charge = number of protons  - number of electrons  = 11 - 10  = +1

So, we have a Na⁺

4 0
3 years ago
A box has a weight of 150 N and is being pulled across a horizontal floor by a force that has a magnitude of 110 N. The pulling
ivann1987 [24]

Answer:

42.99°

Explanation:

F_h = Kinetic friction force

F_{\theta} = Pulling force at angle \theta

N_h = Weight of the box = 150 N

Kinetic friction force

F_h=\muN_h

Pulling force at angle \theta

F_{\theta}=\muN_{\theta}

N = Pulling force

According to question

\frac{F_h}{F_{\theta}}=\frac{2}{1}\\\Rightarrow \frac{\muN_h}{\muN_{\theta}}=2\\\Rightarrow \frac{N_h}{N_{\theta}}=2\\\Rightarrow N_{\theta}=\frac{N_h}{2}\\\Rightarrow N_{\theta}=\frac{150}{2}\\\Rightarrow N_{\theta}=75\ N

Applying Newton's second law in the vertical direction we get

N_h-Nsin\theta=N_{\theta}\\\Rightarrow 150-110sin\theta=75\\\Rightarrow \theta=sin^{-1}\frac{75}{110}\\\Rightarrow \theta=42.99\ ^{\circ}

The angle is 42.99°

8 0
3 years ago
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