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Delicious77 [7]
2 years ago
14

Imamu’s car is travelling twice as fast as Mosi’s car. Mosi travels 200 km in 2 hours. How long does it take Imamu to travel 50

km?
Physics
1 answer:
soldi70 [24.7K]2 years ago
8 0

Answer:

0.25hr

Explanation:

Given parameters:

Distance  = 200km

Time = 2hrs

  Now, let us find the rate which is the speed;

    Speed  = \frac{distance}{time}  

 Insert parameters:

      Speed  = \frac{200}{2}   = 100km/hr

Since the speed of Imamu = 2 x speed of Mosi = 200km/hr

Time taken  = \frac{distance}{speed}  = \frac{50}{200}   = 0.25hr

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an object of mass 8 kg is whriled round in a vertical circle of radius 2m with a constant speed of 6m/s .Then the maximum and mi
algol13

Answer:

Maximum Tension=224N

Minimum tension= 64N

Explanation:

Given

mass =8 kg

constant speed = 6m/s .

g=10m/s^2

Maximum Tension= [(mv^2/ r) + (mg)]

Minimum tension= [(mv^2/ r) - (mg)]

Then substitute the values,

Maximum Tension= [8 × 6^2)/2 +(8×9.8)] = 224N

Minimum tension= [8 × 6^2)/2 -(8×9.8)]

=64N

Hence, Minimum tension and maximum Tension are =64N and 2224N respectively

5 0
2 years ago
A hiker walks 11 km due north from camp and then turns and walks 11 km due east. What is the magnitude of the displacement (on a
sattari [20]

Answer:

16 km

Explanation:

Drawing a right triangle to model the problem helps. I started by drawing the lines of the triangle to model the hiker's journey- a vertical straight line for 11 km north and then a horizontal line connected to the top of it for 11 km east; I then drew the hypothenuse to connect the two lines.

The hypothenuse is what we have to solve for, so we will use the Pythagorean Theorem, a^2 + b^2 = c^2. Since both distances are 11 km both a and b in the equation are 11.

11^2 + 11^2 = c^2

121 + 121 = c^2

242 = c^2

c = 15.56

Rounding the answer makes it 16 km for the hiker's magnitude of displacement.

5 0
3 years ago
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Firlakuza [10]

Answer:

1.96 N

Explanation:

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3 years ago
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