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Delicious77 [7]
2 years ago
14

Imamu’s car is travelling twice as fast as Mosi’s car. Mosi travels 200 km in 2 hours. How long does it take Imamu to travel 50

km?
Physics
1 answer:
soldi70 [24.7K]2 years ago
8 0

Answer:

0.25hr

Explanation:

Given parameters:

Distance  = 200km

Time = 2hrs

  Now, let us find the rate which is the speed;

    Speed  = \frac{distance}{time}  

 Insert parameters:

      Speed  = \frac{200}{2}   = 100km/hr

Since the speed of Imamu = 2 x speed of Mosi = 200km/hr

Time taken  = \frac{distance}{speed}  = \frac{50}{200}   = 0.25hr

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Anastasy [175]

First we will find the speed of the ball just before it will hit the floor

so in order to find the speed of the cart we will first use energy conservation

KE_i + PE_i = KE_f + PE_f

\frac{1}{2}mv_i^2 + mgh = \frac{1}{2}mv_f^2 + 0

\frac{1}{2}(1.25)(52)^2 + 1.25(9.8)(225) = \frac{1}{2}(1.25)v_f^2

So by solving above equation we will have

v_f = 84.3 m/s

now in order to find the momentum we can use

P = mv

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3 0
3 years ago
A thin flake of mica (n=1.58) is used to cover one slit of a double-slit interference arrangement. The central point on the wiew
Llana [10]

To develop this problem it is necessary to apply the optical concepts related to the phase difference between two or more materials.

By definition we know that the phase between two light waves that are traveling on different materials (in this case also two) is given by the equation

\Phi = 2\pi(\frac{L}{\lambda}(n_1-n_2))

Where

L = Thickness

n = Index of refraction of each material

\lambda = Wavelength

Our values are given as

\Phi = 7(2\pi)

L=t

n_1 = 1.58

n_2 = 1

\lambda = 550nm

Replacing our values at the previous equation we have

\Phi = 2\pi(\frac{L}{\lambda}(n_1-n_2))

7(2\pi) = 2\pi(\frac{t}{\lambda}(1.58-1))

t = \frac{7*550}{1.58-1}

t = 6637.931nm \approx 6.64\mu m

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3 0
3 years ago
Hydrogen-2 and Hydrogen-3 fuse to form Helium-4 and a neutron. How much energy is released in this nuclear reaction?
IgorC [24]

1 jul is released after

3 0
3 years ago
Find the relation, time velocity graph : acceleration of an object, time position graph : ?
Anit [1.1K]

Answer:

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slope = velocity

In a time-velocity graph (v-t graph):

slope = acceleration

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In a time-acceleration graph (a-t graph):

area under graph = change in velocity

8 0
3 years ago
008 (part 1 of 3) 10.0 points A 3.2 kg object is subjected to two forces, F~ 1 = (1.9 N) ˆı + (−1.9 N) ˆ and F~ 2 = (3.8 N) ˆı
musickatia [10]

Answer:

a' =4.15 m/s²

Explanation:

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m= 3.2 kg

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F₂=3.8 i −10.1 j N

From second law of Newton's

F(net) = m a

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a = 1.78 i - 3.75 j m/s²

The resultant  acceleration  a'

a'=\sqrt{1.78^2+3.75^2}\ m/s^2

a' =4.15 m/s²

6 0
3 years ago
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