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larisa86 [58]
3 years ago
13

g A 4-foot spring is elongated167feet long after a mass weighing 16 pounds is attached to it. The medium throughwhich the mass m

oves offers a damping force numerically equivalent to92times the instantaneous velocity.(a) Find the equation of motion if the mass is initially released from the equilibrium position with a downwardvelocity of 2 ft/s. (Use the convention that displacements measured below the equilibrium position are positive).(b) What is the velocity of the mass whent
Physics
1 answer:
marta [7]3 years ago
3 0

Answer: hello question b is incomplete attached below is the missing question

a) attached below

b) V = 0.336 ft/s

Explanation:

Elongation ( Xo)  = 16/ 7 feet

mass attached to 4-foot spring = 16 pounds

medium has 9/2 times instanteous velocity

<u>a) Find the equation of motion if the mass is initially released from the equilibrium position with a downward velocity of 2 ft/s</u>

The motion is an underdamped motion because the value of β < Wo

Wo = 3.741 s^-1

attached below is a detailed solution of the question

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If a car travels 600m west in 25 seconds, what is its velocity?
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v =  \frac{ \:the covered distance}{time} \\

v =  \frac{600}{25} =  \frac{6 \times 100}{25} = 6 \times 4 = 24 \:  \\

v = 24 \:  \frac{m}{s} \\

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If west means the west of the axis x the velocity equal :

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3 years ago
An atom is made up of which of the following?
mamaluj [8]

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B electrons protons and neutrons

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Is there carbon atoms in the compound Ca3N2​
katen-ka-za [31]

No, there are not any carbon atoms inside this compound.

The compound is Ca_3N_2. This means there are 3 "Ca" atoms and 2 "N" atoms.

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Thus, none of the elements in this compound are carbon, meaning there are no carbon atoms. Let me know if you need any clarifications, thanks!

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After being struck by a bowling ball, a 1.3 kg bowling pin sliding to the right at 5.0 m/s collides head-on with another 1.3 kg
GuDViN [60]

Answer:

a) 4.2m/s

b) 5.0m/s

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This problem is solved using the principle of conservation of linear momentum which states that in a closed system of colliding bodies, the sum of the total momenta before collision is equal to the sum of the total momenta after collision.

The problem is also an illustration of elastic collision where there is no loss in kinetic energy.

Equation (1) is a mathematical representation of the the principle of conservation of linear momentum for two colliding bodies of masses m_1 and m_2 whose respective velocities before collision are u_1 and u_2;

m_1u_1+m_2u_2=m_1v_1+m_2v_2..............(1)

where v_1 and v_2 are their respective velocities after collision.

Given;

m_1=1.3kg\\u_1=5m/s\\m_2=1.3kg\\u_2=0m/s

Note that u_2=0 because the second mass m_2 was at rest before the collision.

Also, since the two masses are equal, we can say that m_1=m_2=m so that equation (1) is reduced as follows;

mu_1+mu_2=mv_1+mv_2\\\\m(u_1+u_2)=m(v_1+v_2)..............(2)

m cancels out of both sides of equation (2), and we obtain the following;

u_1+u_2=v_1+v_2.............(3)

a) When v_1=0.8m/s, we obtain the following by equation(3)

5+0=0.8+v_2\\hence\\v_2=5-0.8\\v_2=4.2m/s

b) As m_1 stops moving v_1=0, therefore,

5+0=0+v_2\\v_2=5m/s

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3 years ago
What has 12 humps and lives at the north pole?
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<h2>Camels have 12 humps and lives at the North Pole </h2>

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