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Lady_Fox [76]
4 years ago
8

When the balloon hits the ground, it rebounds slightly. What is the source of the energy for this rebound? A. When the balloon h

its the ground, the water warms; this thermal energy is converted to gravitational potential energy of the rebounding balloon. B. As the balloon hits the ground, the edges rise up; this gravitational potential energy is shared with the rest of the balloon. C. When the balloon hits the ground, the rubber envelope stretches, storing elastic potential energy; this elastic potential energy is converted to the gravitational potentiaL
Physics
1 answer:
nevsk [136]4 years ago
7 0

Answer:

The correct answer is c.    When the balloon hits the ground, the rubber envelope stretches, storing elastic potential energy; this elastic potential energy is converted to the gravitational potentiaL

Explanation:

Let's analyze the situation of the globe

When it touches the ground, the part that is in contact decreases its velocity to zero, but the upper part of the ball continues to move, which creates that the molecules approach slightly, if we approximate the spring links, a repulsive force is created that after all the particles reach zero speed. The force of the springs moves the ball up until the force decreases to zero.

We can relate this force of Hooke with an elastic energy

This energy can be stored in the deformation of the system, as elastic potential energy, which is subsequently transformed into gravitational potential energy when the balloon is lifted.

The correct answer is c

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3 years ago
The magnetic flux through a metal ring varies with time t according to ΦB = at3 − bt2, where ΦB is in webers, a = 6.00 Wb s−3, b
pychu [463]

To solve this problem it is necessary to apply the second derivative of the function to find the maximum time reference and thus calculate the maximum voltage.

With the maximum voltage by Ohm's Law it is possible to find the maximum current.

Ohm's law defines that

E = I*R

Where,

I = Current

R= Resistance

On the other hand by faraday studies and the potential can be expressed at the rate of change of the electric flow, that is

E = \frac{d\phi}{dt}

Replacing with our values we have that

E = \frac{d(6t^3-18t^2)}{dt}

E = -18t^2 +36t

The second derivative is

E' = -36t+36

When E' = 0 we have a Maximum, then

0 = -36t+36

t = 1

Therefore when the time is 1s E has a Maximum, replacing at the function

E(t) = -18t^2 +36t

E(1) = -18(1)^2 +36(1)

E = 18V

Then the maximum current will be given by

I = \frac{E}{R}

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6 0
4 years ago
2. A car is traveling with a velocity of 40 m/s and has a mass of 1,120 kg. Calculate the kinetic energy.
klasskru [66]

Answer:

896,000 J

Explanation:

m = 1,120 kg

v = 40 m/s

kinetic energy = mv^2/2 = 1,120 * 40^2/2= 896,000 J

7 0
3 years ago
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