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3 years ago

When do cells use oxygen to release energy

1 answer:

7 0

According to the theory, energy realized during the reaction is captured by the energy-carrying molecule ATP (adenosine triphosphate). Cellular respiration is the process by which organism use oxygen to break down food molecule to get chemical energy for cell function

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Weigt A box sitting still on the ground by itself has a weight of 700N, what is the mass? (gravity's acceleration is 9.80 m/s2)

Alex

Force=700N
Acceleration=9.8m/s^2

Using newtons law

$\\ \rm\longmapsto F=ma$

$\\ \rm\longmapsto m=\dfrac{F}{a}$

$\\ \rm\longmapsto m=\dfrac{700}{9.8}$

$\\ \rm\longmapsto m=71.4kg$

7 0

3 years ago

A car accelerates uniformly from rest to 23 m/s over a distance of 30 meters. What is the acceleration of the car?

kolezko [41]

Answer:

a= 17.69 m/s^2

Explanation:

Step one:

given data

A car accelerates uniformly from rest to 23 m/s

u= 0m/s

v= 23m/s

distance= 30m

Step two:

We know that

acceleration= velocity/time

also,

velocity= distance/time

23= 30/t

t= 30/23

t= 1.30 seconds

hence

acceleration= 23/1.30

accelaration= 17.69 m/s^2

3 0

3 years ago

A ball is thrown vertically upwards at 19.6 m/s. For its complete trip (up and back down to the starting position), its average

stira [4]

When the ball reaches its original position, it will have the same speed (but would be traveling in the opposite direction). So the average speed is

$\dfrac{19.6\,\frac{\mathrm m}{\mathrm s}-19.6\,\frac{\mathrm m}{\mathrm s}}{\Delta t}=0$

regardless of how long the ball was in the air.

5 0

3 years ago

For each 1 degree Celsius that temperature incileases, the speed of<br> sound ___ by 0.6 m/s.

Levart [38]

Answer:

A: For each 1 degree Celsius that temperature decreases, the speed of sound decreases by 0.6 m/s. So sound travels through dry, -20 °C air at a speed of 319 m/s

Explanation:

6 0

3 years ago

ball dropped from top of 50m high cliff stone thrown straight up from bottom with speed of 24. they collide. how far above base

Tresset [83]

Answer:

28.73 m from the base of the cliff collide happen

Explanation:

Equation for ball dropped from 50 cliff is reaches distance x in t seconds isi given by

$x=ut+\frac{1}{2} at^2\\\\x= 0 \times t+\frac{1}{2} gt^2 =\frac{1}{2} gt^2......(1)$

stone is thrown up from the bottom with speed u=24 m/s . it reaches distance y when stone collide with ball.(g is negative here)

$y=24t-\frac{1}{2} gt^2.............(2)$

we know that total distance traveled by ball and stone is 50 m

$x+y=50 m$

adding equation 1 and 2, we get time t

$x+y=\frac{1}{2} gt^2+24t-\frac{1}{2}gt^2\\50=24t\\t=2.083 s$

substitute this time in equation 2, we can get the required distance where they collide

$y=24t-\frac{1}{2} gt^2\\y=24\times 2.083-\frac{1}{2}\times 9.8\times 2.083^2\\y=28.73 m$

28.73 m from the base of the cliff collide happen

7 0

3 years ago