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Alexandra [31]
3 years ago
11

When do cells use oxygen to release energy

Physics
1 answer:
Dimas [21]3 years ago
7 0
According to the theory, energy realized during the reaction is captured by the energy-carrying molecule ATP (adenosine triphosphate). Cellular respiration is the process by which organism use oxygen to break down food molecule to get chemical energy for cell function
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A charge Q is uniformly spread over one surface of a very large nonconducting square elastic sheet having sides of length d. At
GuDViN [60]

Answer:

E/4

Explanation:

The formula for electric field of a very large (essentially infinitely large) plane of charge is given by:

E = σ/(2ε₀)

Where;

E is the electric field

σ is the surface charge density

ε₀ is the electric constant.

Formula to calculate σ is;

σ = Q/A

Where;

Q is the total charge of the sheet

A is the sheet's area.

We are told the elastic sheet is a square with a side length as d, thus ;

A = d²

So;

σ = Q/d²

Putting Q/d² for σ in the electric field equation to obtain;

E = Q/(2ε₀d²)

Now, we can see that E is inversely proportional to the square of d i.e.

E ∝ 1/d²

The electric field at P has some magnitude E. We now double the side length of the sheet to 2L while keeping the same amount of charge Q distributed over the sheet.

From the relationship of E with d, the magnitude of electric field at P will now have a quarter of its original magnitude which is;

E_new = E/4

3 0
3 years ago
Vascular resistance is the friction force that opposes blood flow in a blood vessel. what two factors are the most important in
makvit [3.9K]
The two most important factors are Systematic Vascular Resistance as and Vascular Resistance.
6 0
3 years ago
The electrostatic force between two charges is 1.8 × 10–6 N when q1 = q2; that is, when the charges are equal in magnitude. If t
guajiro [1.7K]

Answer:

Doubled

Explanation:

F = 1.8 x 10^-6 N, q1 = q2

The force between the two charges is directly proportional to the product of two charges and inversely proportional to the square of distance between them.

Now one of the charge is doubled but the distance remains same so the force between the two charges becomes doubled.

6 0
3 years ago
The third-order bright fringe of 610-nm light is observed at an angle of 31° when the light falls on two narrow slits. How far a
Anna11 [10]

Answer:

The distance between the slits is 3.55 μm

Explanation:

Given that,

Order number = 3

Wave length = 610 nm

Angle = 31°

We need to calculate the distance between the slits

Using formula of distance of slit

d\sin\theta=n\lambda

d=\dfrac{n\lambda}{\sin\theta}

Where, n = order number

\lambda= wavelength

Put the value into the formula

d=\dfrac{3\times610\times10^{-9}}{\sin31}

d=3.55\times10^{-6}\ m

d= 3.55\ \mu m

Hence, The distance between the slits is 3.55 μm.

8 0
3 years ago
Which element is classified as an alkali metal?
Alex73 [517]
According to the periodic table, all the elements, except hydrogen, are considered alkaline metals. ie. Li, Na, K, Rb, Cs, Fr.
6 0
3 years ago
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