Which acceleration graph corresponds to the pressure graph shown?

A string attached to an airborne balloon was maintained at an angle of 54 degrees with the ground. If 2.3 m of string was reeled

Slav-nsk [51]

Answer:

dₓ = 1.35 m

dy = 1.86 m

Explanation:

In order to find the vertical and horizontal components of the displacement, we can assume a right triangle. Such that, the length of string is the hypotenuse, making and angle of 54° with the base of triangle. The base is the horizontal component of displacement. And the perpendicular is the vertical component of displacement. Therefore:

$d_{x} = d\ Cos\ \theta$

where,

dₓ = horizontal component of displacement = ?

d = resultant displacement = 2.3 m

θ = angle between displacement and ground = 54°

Therefore,

$d_{x} = (2.3\ m)\ Cos\ 54^0$

For vertical component of displacement:

$d_{y} = d\ Sin\ \theta\\d_{y} = (2.3\ m)\ Sin\ 54^0$

8 0

3 years ago

How efficient is a pulley system if an operator has to pull 2.5m of rope to lift a 250 N pail of water a distance of 4.5 m?

Alik [6]

Answer:

the pulley system is very efficient

Explanation:

Given;

load, L = 250 N

distance moved by the load, a = 4.5 m

distance moved by the effort, e = 2.5 m

let the force or effort applied = F

Apply the principle of conservation of energy;

F x e = L x a

F = (L x a) / e

F = (250 x 4.5) / 2.5

F = 450 N

The efficient of the pulley system;

E = Output force / Input force

E = (450 x 2.5) / (250 x 4.5)

E = 1 = 100%

Therefore, the pulley system is very efficient

4 0

3 years ago

An eagle is flying horizontally at a speed of 2.60 m/s when the fish in her talons wiggles loose and falls into the lake 4.60 m

sergij07 [2.7K]

Answer:

9.495 m/s

Explanation:

initial horizontal speed, ux = 2.60 m/s

initial vertical speed, uy = 0

height, h = 4.60 m

acceleration due to gravity, g = 9.8 m/s^2

Let the speed of fish is v as it hits the water level.

Use third equation of motion in vertical direction

$v^{2}= u^{2}+2as$

$v^{2}= 0^{2}+2\times 9.8\times 4.60$

v = 9.495 m/s

Thus, the fish hits the water level with the speed of 9.495 m/s.

8 0

3 years ago

A motorboat sets out for open sea. From home it travels 5 km due East, then heads [N35E] at 2 m/s for 90 minutes. After a break,

geniusboy [140]

The distance of the motorboat relative to the home, which travels in various directions, is 3.07 km.

<h3>What is relative velocity?</h3>

Relative velocity is a velocity of an object which is in respect to another observer, or it is a ratio of change in the position of a point to time with respect to another observer.

Given: Travel in East direction ( $d_{E}$ )= 5 km,

velocity in N35E(v) = 2 m / s, time taken(t) = 90 min = 5400 seconds,
Displacement in south ( $D_S}$ ) = 6.5 km

Firstly, find the displacement in N35E so

Displacement = Velocity × time,

$d_{NE}$ = 2 × 5400 = 10800 meters or 10.8 km

Now by using Pythagoras' theorem
We can calculate the return displacement in the south direction( $d_{S}$ ),

$d_{S}$ = $\sqrt{d^{2} _{NE}- d^{2} _{E } }$
$d_{S}$ = $\sqrt{10.8^{2}-5^{2} }$

$d_{S}$ = 9.57 km

Therefore, the distance of the boat from the home (D) = $d_S}$ - $D_S}$

D = 9.57 - 6.5;

D = 3.07 Km

To know more about Relative velocity:

brainly.com/question/19260269

#SPJ1

3 0

1 year ago

What is the input of energy for a device that provides 50 units of useful energy and has an efficiency of 0.55?

marshall27 [118]

If that's the case, then

      50 units = 0.55 x the input energy

Divide each side by 0.55 :

   50 units/0.55 = the input energy =

   <em> 90 and 10/11 units</em>

3 0

4 years ago