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Mashcka [7]
3 years ago
12

A 22 kg sled is pushed for 5.2 m with a horizontal force of 20 N, starting from rest. ignore friction. find the final speed of t

he sled.
2.2 m/s
4.7 m/s
9.5 m/s
3.1 m/s
Physics
1 answer:
maksim [4K]3 years ago
5 0
We first calculate the friction on the sled using:
F = ma
a = 20 / 22
a = 0.91 m/s²

Now we use the formula:
2as = v² - u²
v = √(2as + u²)
v = √[2(0.91)(5.2) + 0]
v = 3.08 m/s
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Vector ~A has a magnitude of 29 units and points in the positive y-direction. When vector ~B is added to ~A, the resultant vecto
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Answer:

The magnitude of vector B is 43 units and it points in the negative y-direction.

Explanation:

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Vector A = 29j

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R = A + B

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Answer:

The magnitude of momentum of the airplane is 6.83\times 10^5\ kg-m/s.

Explanation:

Given that,

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v = 201.16 m/s

We need to find the magnitude of momentum of the airplane. It is given by the product of mas and velocity such that,

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So, the magnitude of momentum of the airplane is 6.83\times 10^5\ kg-m/s. Hence, this is the required solution.

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