Answer:
Explanation:
None of the other answers matter but the right answer which A. Silicon has an outer shell of 4. Carbon can connect with 4 elements because of its outer shell. CH4 is the simplest example. But C2H6 is also possible.
H H
H - C - C - H
H H
There are 4 connections to the outside world for the Carbon (C) on the left.
It has 3 hydrogens connected on to it and one of its connecting electrons goes with the other carbon on the right.
Silicon can do the same thing.
It's false i hope this helps :)
(a) The magnitude of the net force on the crate is -26.46 N.
(b) The net work done on the crate while it is on the rough surface is -17.2 J.
(c) The speed of the crate when it reaches the end of the rough surface is 0.61 m/s.
<h3>Magnitude of net force on the crate</h3>
The magnitude of the net force on the crate is calculated as follows;
F(net) = F - Ff
where;
F(net) = F - μmg
F(net) = 290 - (0.351)(92)(9.8)
F(net) = -26.46 N
<h3>Net work done on the crate</h3>
W = Fd
W = -26.46 x 0.65 = - 17.2 J
<h3>Speed of the crate </h3>
acceleration of the crate, a = F/m
a = -26.46/92
a = -0.288 m/s²
v² = u² + 2as
v² = 0.865² + (2)(-0.288)(0.65)
v² = 0.374
v = 0.61 m/s
Learn more about net force here: brainly.com/question/25239010
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Answer:
While traveling downhill, the car’s potential is <u>increasing</u> and kinetic energy is <u>decreasing</u>
Explanation:
hope this helps!
Answer:
Friction force is 0.1375 N
Solution:
As per the question:
Radius of the metal disc, R = 4.0 cm = 0.04 m
Magnetic field, B = 1.25 T
Current, I = 5.5 A
Force on a current carrying conductor in a magnetic field is given by considering it on a differential element:
![dF = IB\times dR](https://tex.z-dn.net/?f=dF%20%3D%20IB%5Ctimes%20dR)
Integrating the above eqn:
![\int dF = IB\int_{0}^{R}dr](https://tex.z-dn.net/?f=%5Cint%20dF%20%3D%20IB%5Cint_%7B0%7D%5E%7BR%7Ddr)
(1)
Now the torque is given by:
(2)
From eqn (1) and (2):
![F\times R = \frac{1}{2}IBR^{2}](https://tex.z-dn.net/?f=F%5Ctimes%20R%20%3D%20%5Cfrac%7B1%7D%7B2%7DIBR%5E%7B2%7D)
Thus the Frictional force is given by:
![F = \frac{1}{2}\times 5.5\times 1.25\times 0.04 = 0.1375\ N](https://tex.z-dn.net/?f=F%20%3D%20%5Cfrac%7B1%7D%7B2%7D%5Ctimes%205.5%5Ctimes%201.25%5Ctimes%200.04%20%3D%200.1375%5C%20N)