Answer:
The new volume of the gas decreased in to 0.329llL
Answer:
Explanation:
x in (-oo:+oo)
2 < (1/2)*x-3 // - (1/2)*x-3
2-((1/2)*x)+3 < 0
(-1/2)*x+2+3 < 0
5-1/2*x < 0 // - 5
-1/2*x < -5 // : -1/2
x > -5/(-1/2)
x > 10
x in (10:+oo)
(10:+oo)
Answer:
Hydrogen bond strengths range from 4 kJ to 50 kJ per mole of hydrogen bonds. In molecules containing N-H, O-H or F-H bonds, the large difference in electronegativity between the H atom and the N, O or F atom leads to a highly polar covalent bond (i.e., a bond dipole).
Explanation:
We are given that the concentration of the KCl is 2 meq /
mL. Assuming that the ampule also has exactly this concentration, therefore:
amount of KCl in ampule = (2 meq / mL) * (20 mL)
amount of KCl in ampule = 40 meq
This amount of KCl is now inside a solution of 1 Liter (also
equivalent to 1000 mL), therefore the new concentration in the resulting
solution is:
new concentration = 40 meq / 1000 mL
new concentration = 0.04 meq / mL
Since 0.04 in decimal is 4% in percentage, therefore the
strength of the resulting solution is 4% KCl.
The answer is; D
Solvation is the process by which the molecules of a solute interact with those of a solvent to form solvates. The interaction involves the formation of temporary bonds between the molecules of the elements. These bonds in this rection absorb energy from the atmosphere hence the reaction feels cold to the touch. This is called an endothermic reaction.