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Anna [14]
3 years ago
10

Which particles form the nucleus of an atom?

Chemistry
2 answers:
LiRa [457]3 years ago
8 0

Answer:

Lit

Explanation:

The nucleus of an atom consists of neutrons and protons, which in turn are the manifestation of more elementary particles, called quarks, that are held in association by the nuclear strong force in certain stable combinations of hadrons, called baryons.

Lisa [10]3 years ago
4 0

Answer:

i believe its neutrons and protons

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is trying to plate gold onto his silver ring. He constructs an electrolytic cell using his ring as one of the electrodes. He run
notka56 [123]

Answer:

0.013 mole.

Explanation:

From the question given above, the following data were obtained:

Time (t) = 94.6 mins

Current (I) = 224.8 mA.

Mole of electrons (e) =?

Next, we shall convert 94.6 mins to seconds. This is illustrated below:

1 min = 60 s

Therefore,

94.6 mins = 94.6 min × 60 s / 1 min

94.6 mins = 5676 s

Thus, 94.6 mins is equivalent to 5676 s.

Next, we shall convert 224.8 mA to ampere (A). This can be obtained as follow:

1 mA = 1×10¯³ A

Therefore,

224.8 mA = 224.8 mA × 1×10¯³ A / 1 mA

224.8 mA = 0.2248 A

Thus, 224.8 mA is equivalent to 0.2248 A.

Next, we shall determine the quantity of electricity flowing in circuit. This can be obtained as follow:

Time (t) = 5676 s

Current (I) = 0.2248 A

Quantity of electricity (Q) =?

Q = it

Q = 0.2248 × 5676

Q = 1275.96 C

Finally, we shall determine the mole of electron by converting the quantity of electricity (i.e 1275.96 C) to number of electrons. This can be obtained as follow:

96500 C = 1 e

Therefore,

1275.96 C = 1275.96 C × 1 e / 96500 C

96500 C = 0.013 e

Thus, the mole of electron trasfered in the process is 0.013 mole.

3 0
3 years ago
The Ksp for CaF2 is 3.9 x 10-11 at 25oC. What is the solubility?
nevsk [136]

We have to know the solubility of CaF₂.

The solubility of CaF₂ is: (c) 2.1 x 10-4 Molar

The general expression of solubility product of any sparingly soluble salt (having solubility S) with formula A_{x} B_{y} is: x^{x} y^{y} S^{x+y}.

For the compound, CaF₂, x=1, y=2 So, K_{sp}=1^{1}2^{2}S^{1+2}=4S³= 3.9 x 10-11  (Given)

S³=\frac{3.9 X 10^{-11} }{4}

S³=9.75  X 10^{-12}

S= 2.1 X 10^{-4} Molar

5 0
4 years ago
Read 2 more answers
The power has gone out and you find a flashlight that uses batteries. When you turn on the flashlight, you are transforming:
Semenov [28]
In a flashlight, the electrical energy becomes light energy and thermal energy in the bulb.
5 0
3 years ago
Read 2 more answers
Help please i’ll give extra points
joja [24]

Answer:

okay no problem

I will give

7 0
3 years ago
At 920 K, Kp = 0.40 for the following reaction. 2 SO2(g) + O2(g) equilibrium reaction arrow 2 SO3(g) Calculate the equilibrium p
Alex777 [14]

<u>Answer:</u> The equilibrium partial pressure of sulfur dioxide, oxygen and sulfur trioxide is 0.366 atm, 0.443 atm and 0.154 atm respectively.

<u>Explanation:</u>

We are given:

Initial partial pressure of sulfur dioxide = 0.52 atm

Initial partial pressure of oxygen = 0.52 atm

Initial partial pressure of sulfur trioxide = 0 atm

For the given chemical reaction:

                        2SO_2(g)+O_2(g)\rightleftharpoons 2SO_3(g)

<u>Initial:</u>                 0.52      0.52

<u>At eqllm:</u>         0.52-2x    0.52-x        2x

The expression of K_p for above equation follows:

K_p=\frac{(p_{SO_3})^2}{(p_{SO_2})^2\times p_{O_2}}

We are given:

K_p=0.40\\\\p_{SO_3}=2x\\\\p_{SO_2}=0.52-2x\\\\p_{O_2}=0.52-x

Putting values in above equation, we get:

0.40=\frac{(2x)^2}{(0.52-2x)^2\times (0.52-x)}\\\\x=-1.13,-0.402,0.077

Neglecting the negative values because partial pressure cannot be negative.

So, x = 0.077

Equilibrium partial pressure of sulfur dioxide = (0.52-2x)=(0.52-(2\times 0.077))=0.366atm

Equilibrium partial pressure of oxygen = (0.52-x)=(0.52-0.077)=0.443atm

Equilibrium partial pressure of sulfur trioxide = 2x=(2\times 0.077)=0.154atm

Hence, the equilibrium partial pressure of sulfur dioxide, oxygen and sulfur trioxide is 0.366 atm, 0.443 atm and 0.154 atm respectively.

4 0
3 years ago
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