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vampirchik [111]
3 years ago
12

Compute 4.659×104−2.14×104. Round the answer appropriately.

Chemistry
2 answers:
IrinaK [193]3 years ago
7 0
<span>To compute 4.659×104−2.14×104, the first step is the factorization. That is as follows:4.659×104−2.14×104= 10^4.(4.659−2.14), the next step is to compute 4.659−2.14=2.51, so 10^4.(4.659−2.14)=2.51x10^4=2.51x 10000 (because10^4=10000), the last calculus is 2.51x 10000=25100, the final answer is 25,000.Hope this helps. Let me know if you need additional help!</span>
Effectus [21]3 years ago
3 0

Answer is: proper number of significant figures is 25190.00.

10⁴ = 10×10×10×10.

10⁴ = 10000.

1) 4.659×10⁴ = 4.659×10000.

4.659×10⁴ = 46590.

2) 2.14×10⁴ = 2.14×10000.

2.14×10⁴ = 21400.

3) 4.659×10⁴ - 2.14×10⁴ = 46590 - 21400.

4.659×10⁴ - 2.14×10⁴ = 25190 (2.519×10⁴).

An integer is a number that can be written without a fractional component.

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The symbol for xenon (xe) would be a part of the noble gas notation for the element cesium.

For writing the electronic configuration of any element by using the preceding noble gas configuration, we simply use the symbols of noble gas belongs to the previous period of that particular elements. We can't use the symbol of noble gas of same period from which the element belong.

A is the wrong option because the noble gas in the preceding period to the period from which antimony belongs is krypton.

The actual electronic configuration of antimony is as follow:

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B is correct option because the noble gas in the preceding period to the period from which Cesium belongs is Xenon.

The actual electronic configuration of Cesium is as follow:

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Explanation:

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Perform the following mathematical operation, and report the answer to the correct number of significant figures. 0.34 x 0.568=?
slavikrds [6]

The correct answer to the problem is 0.193 which is three significant figures.

<h3>What are significant figures?</h3>

The term significant figures has to do with the figures that have a mathematical meaning. We know that the result has to correspond to the highest number of significant figures.

Hence, If we multiply 0.34 x 0.568 the result ought to be recorded as 0.193 which is three significant figures.

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